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4vir4ik [10]
3 years ago
9

What improper fraction is the same as 12 3/4? A) 51/4 B) 12/4 C) 123/4 D) 48/4

Mathematics
2 answers:
lbvjy [14]3 years ago
8 0

51/4 because you multiply 12*4 which is 48 and add 3 so you get 51. You keep the denominator so you should get 51/4.

DIA [1.3K]3 years ago
5 0

Answer:

A

Step-by-step explanation:

Convert the mixed number in the question to a improper fraction and cross multiply to see if they equal the same

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GarryVolchara [31]
B is as it is a logical form of reasoning. if a=50, b=30, c=20
if a > b and b > c then a > c
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Tony is mailing packages. Each small package costs him $2.80 to send. Each large package costs him $3.60. How much will it cost
Natasha_Volkova [10]

Answer:

The answer is $33.6

Step-by-step explanation:

Each small package costs him $2.80

3 small packages will cost him 3 x $2.80 = $8.4

 

Each large package costs him $3.60

7 large packages will cost 7 x $3.60 = $25.2

 

Cost to  send 3 small packages and 7 large packages = $8.4 + $25.2

= $33.6

6 0
3 years ago
2. Tyler can type 50 words per minute. He needs to finish typing his 500-word
nikdorinn [45]

Answer:

9.5 minute

Step-by-step explanation:

500 - 25 = 50x

x  = \frac{475}{50}

x = 9.5 minute

6 0
3 years ago
[4]
Tanya [424]

Answer:

Angle ACD = 38°

Step-by-step explanation:

The full, correct question is presented the attached image to this solution.

Given

Point O is the centre if the circle

Points A, B, C and D are points on the circle

Angle AOB = 140°

Angle OAC = 14°

Angle AOB = 2 × (Angle ACB) [angle subtended at the centre of the circle is twice the angle subtended at the circumference of the circle)

140° = 2 × (Angle ACB)

Angle ACB = (140°/2) = 70°

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180° [sun of angles in a triangle is 180°]

But Angle OAB = Angle ABO = a [base angles of an iscosceles triangle are equal since OA and OB are both radii for the circle O)

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180°

140° + a + a = 180°

2a = 40°

a = (40/2) = 20°

Angle OAB = Angle ABO = 20°

Angle CAB = (Angle OAC) + (Angle OAB) = 14° + 20° = 34°

Triangle ADC is an iscosceles triangle, hence,

Angle DAC = Angle ACD = x [base angles of an iscosceles triangle are equal]

But

(Angle DCB) + (Angle DAB) = 180° [Opposite angles of a cyclic quadilateral (a quadilateral inscribed in a circle) sum up to give 180°]

Angle DCB = (Angle DCA) + (Angle ACB) = (x + 70°)

Angle DAB = (Angle DAC) + (Angle CAB) = (x + 34°)

(Angle DCB) + (Angle DAB) = 180°

(x + 70°) + (x + 34°) = 180°

2x + 104° = 180°

2x = 180° - 104° = 76°

x = (76°/2) = 38°

Angle DAC = Angle ACD = 38°

Angle ACD = 38°

Hope this Helps!!!

7 0
3 years ago
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Answer:

The Answer is 18

Step-by-step explanation:

2 1/4 X 8= 18

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