Your anwer is C)<span>f(x) = 467(5 to the one fourth power)4x</span>
<span>Here let the quadratic equation be ax^2 + bx + c
We know that a=5 from the question.
Since the roots are 6 and 2, the quadratic equation would take the form of a product like (a1x-b1)(a2x-b2).
However, let's assume that a2=1 and b2=6,
Since a=5, a1=5, then 5x-b1=5(x-2). Solving this shows that b1=10
So, the equation is (5x-10)(x-6)</span>
Answer: 53.2
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
1/3 x 4 = 1.333....
1.333.... x 9 = 12
12 x 1/2 = 6
Answer:
Step-by-step explanation:
2x + 3y = 2
x = 2 - 3y /2
x + y = 0
substitute the value of x
+ y = 0
2 - 3y + 2y = 0
2 = y
again,substitute the value of y
x = 2 - 3y / 2
=2 - 3*2 / 2
=2 - 6 / 2
=-2
