Answer:
A .cos(x)<1
Step-by-step explanation:
According to the first inequality
cos(x)<1
x < arccos 1
x<0
This therefore does not have a solution within the range 0 ≤ x ≤ 2pi
x cannot be leas than 0. According to the range not value, 0≤x which is equivalent to x≥0. Thus means otvis either x = 0 or x> 0.
For the second option
.cos(x/2)<1
x/2< arccos1
x/2<0
x<0
This inequality also has solution within the range 0 ≤ x ≤ 2pi since 0 falls within the range of values.
For the inequality csc(x)<1
1/sin(x) < 1
1< sin(x)
sinx>1
x>arcsin1
x>90°
x>π/2
This inequality also has solution within the range 0 ≤ x ≤ 2pi since π/2 falls within the range of values
For the inequality csc(x/2)<1
1/sin(x/2) < 1
1< sin(x/2)
sin(x/2)> 1
x/2 > arcsin1
X/2 > 90°
x>180°
x>π
This value of x also has a solution within the range.
Therefore option A is the only inequality that does not have a solution with the range.
I do not know because i’m not good at math
Your answer would be A 1040.
4 would be your answer hope I helped :)
The linear function with the same y-intercept with the graphed function is: table A.
<h3>What is a Linear Function?</h3>
The equation that models a linear function is, y = mx + b, where m is the slope and b is the y-intercept.
Slope of the graphed function = rise/run = - 2/1 = -2
Using one of the points on the line (x, y) = (5, 0) and the slope, m = -2, find the y-intercept (b) by substituting the values into y = mx + b:
0 = -2(5) + b
0 = -10 + b
10 = b
b = 10
The slope (m) of the graphed function is -2, and the y-intercept (b) is: 10.
Slope (m) of table A = change in y/change in x = (14 - 8)/(3 - 1) = 3
Substitute a point (x, y) = (1, 8) and slope (m) = 3 into y = mx + b to find the y-intercept (b):
8 = 3(1) + b
8 - 3 = b
5 = b
b = 5
Therefore the table with the same y-intercept as the graphed function is table A.
Learn more about linear function on:
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