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aalyn [17]
3 years ago
13

The living spaces of all homes in a city have a mean of 2300 square feet and a standard deviation of 500 square feet. Let x be t

he mean living space for a random sample of 25 homes selected from this city.
Find the mean and standard deviation of the sampling distribution of x.
Mathematics
1 answer:
antoniya [11.8K]3 years ago
3 0

Answer:

the mean and standard deviation is 2300 and 100 respectively

Step-by-step explanation:

Given that

Mean = 2300

Standard deviation = 500

let us assume the x be the mean of living space

And, the sample is of 25 homes

We need to find out the mean and the standard deviation

So here mean = 2300

And, the standard deviation

= 500 ÷√25

= 500 ÷ 5

= 100

hence, the mean and standard deviation is 2300 and 100 respectively

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What is the answr to -5(b + 1) = 8
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Quadrilateral RPQS is a rectangle. Label the missing measures.
Taya2010 [7]

Answer:

Part 1) PR=9\ units

Part 2) PQ=12\ units

Part 3) PS=15\ units

part 4) QR=15\ units

Part 5) RT=7.5\ units

Step-by-step explanation:

we know that

In a rectangle opposite sides are parallel and congruent

The measure of each interior angle is 90 degrees

The diagonals are congruent and bisect each other

step 1

Find the length of side PR

we know that

PR=QS ----> by opposite sides

we have

QS=9\ units

therefore

PR=9\ units

step 2

Find the length of side PQ

we know that

PQ=RS ----> by opposite sides

we have

RS=12\ units

therefore

PQ=12\ units

step 3

Find the length of diagonal PS

we know that

PS=2PT---> the diagonals bisect each other

we have

PT=7.5\ units ---> given problem

therefore

PS=2(7.5)=15\ units

step 4

Find the length of diagonal QR

we know that

QR=PS---> the diagonals are congruent

we have

PS=15\ units

therefore

QR=15\ units

step 5

Find the length of RT

we know that

QR=2RT---> the diagonals bisect each other

we have

QR=15\ units

substitute

15=2RT\\RT=7.5\ units

7 0
3 years ago
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