The vertex of the graph of f(x)= |x-3|+6 is located at (3, 6)
<h3>How to determine the vertex?</h3>
The equation of the function is given as:
f(x) = |x - 3| + 6
The above function is an absolute value function.
An absolute value function is represented as:
f(x) = a|x - h| + k
Where:
Vertex = (h, k)
By comparison, we have:
Vertex = (3, 6)
Hence, the vertex of the graph of f(x)= |x-3|+6 is located at (3, 6)
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925 rounded to the nearest hundred is 900 becuase first we identify the hundreds digit which in this case is 9.
Second,we identify the next smallest place value (the digit to the right of the hundreds place) which in this case is 2.
Is that digit greater than or equal to five? No - we round Down.
The hundreds digit is stays the same but every digit after it becomes a zero.
14/15 - 5/12
Common denominator is 60.
56/60 - 25/60
= 31/60 as fraction.
= 0.516 as decimal.
Answer:
-7b+3
Step-by-step explanation:
first step you will find numbers if you take -2.2 to get those numbers
