A cube is shown. What is the surface area of the cube?

Mathematics

2 answers:

valkas [14]3 years ago

4 0

1350 cm^2. First, we must find the area of one side. The formula for the area of a square is S^2 or S*S, so plugging in the value of the side we get 15*15=225. So each side of the cube is 225 cm^2, so since there are 6 sides, we just multiply by 6 (225*6=1350).

posledela3 years ago

4 0

Answer:

Step-by-step explanation:

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What is the producr of 5 and 1/8

timofeeve [1]

There are two easy ways.
The way I was taught:
1. Make 1/8 a decimal by dividing 1 by 8 (Numerator by denominator.), leaving you with 5*.125=.625, or 5/8.
The ACTUAL easy way:
2. Make 5 a fraction by putting it over 1, giving you 5/1*1/8, leaving you with 5/8.

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4 years ago

Read 2 more answers

Graph the system of inequalities presented here on your own paper, then use your graph to answer the following questions:

grigory [225]

Answer:

Part A: The graph of the system is plotted at y-intercepts of 3 and -4. The line of the first equation is dashed and shaded below. The line of the second equation is dashed and shaded above. The solution area is between the second and third quadrants.

Part B: No, the point (-4, 6) is not in the solution are because it only fits into the first equations solution area. [6=2(-4)+3 solved is 6=-5, this is not a true statement.]

Step-by-step explanation:

Part A: Each equation {y>2x+3, y<-3/2x-4} is already in slope intercept form and can be graphed. In the first equation we know that there is a y-intercept of 3 and a slope of 2. This is shown as as a upward moving line with plot points such as (-2,-1), (-1,1), (0,4), (1,6), and so on. In the second equation we know that there is a y-intercept of -4 and a slope of -3/2. This is shown as a downward moving line with plot points such as (0,-4), (-2,-1), (-4, 2), and so on. (See graph below)

Part B: The plot point (-4, 6) is not included in the solution area of the systems. This can be seen on the graph. And, proven mathematically by plugging in the point into the equations: