Answer:
x^2+y^2=16
Step-by-step explanation:
i think so
<span>assume z = ax for simplicity
z(z) = a(ax) = a^2x
let a^2x = 1/16x and solve for a </span>
Answer:
No, to be a function a relation must fulfill two requirements: existence and unicity.
Step-by-step explanation:
- Existence is a condition that establish that every element of te domain set must be related with some element in the range. Example: if the domain of the function is formed by the elements (1,2,3), and the range is formed by the elements (10,11), the condition is not respected if the element "3" for example, is not linked with 10 or 11 (the two elements of the range set).
- Unicity is a condition that establish that each element of the domain of a relation must be related with <u>only one</u> element of the range. Following the previous example, if the element "1" of the domain can be linked to both the elements of the range (10,11), the relation is not a function.
If the value of the baseball card increases by 3% per year then we can say that each year the value of the card may be multiplied by 103% = 1.03, thus:
Value after n years = original price*(1.03)^n
Value after 15 years = 75*(1.03)^15
= $116.85
Answer:
8·549516
Step-by-step explanation:
To round the number given to 6 decimal place, we will follow the steps below;
First count six digits after the decimal point
Then after the six digit number take the next number and see if it below 5 then this means you will be rounding down, so you will leave your six digit after the decimal points the way they are and discard the other digits after the the six digits, but if the digit number right after the sixth digit is 5 and above, then you will be rounding up, you will add one to your sixth digit and then discard the digits after the sixth digits.
That is;
In the number given: 8.54951607694
The sixth digit after the decimal point is 6, the number that comes after it is zero, so we will leave the 6 the way it is and discard the other digits after 6
8.54951607694 ≈ 8·549516 to 6 decimal place
