Answer:
59 minutes
Step-by-step explanation:
In the table of values it is observed that for each day of training 2 minutes are increasing and that day 1 begins with 5 minutes of training
, so
, where x= evaluation day
we have to for the day 28
15=-4+z/3
+4 +15 = +4 -4 +z/3
cancels the 4 on the right side
19 = z/3
3 x 19 = z/3 x 3
cancels 3 on the right side
I think the answer is z = 57
The second option.
Basically, you can use SAS.
Answer:
-15 < 20
Step-by-step explanation:
5(w - 3) < 5w + 20
Distribute;
5w - 15 < 5w + 20
Subtract 5w from both sides;
-15 < 20
<h3>Sample space = {a,b,c,d,e,f}</h3><h3>Event space = {a,c}</h3>
We simply list all of the letters mentioned as they are the possible outcomes. We can only pick one item from the sample space. The event space is the set of outcomes where we want to happen (picking either an 'a' or 'c').
