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Natasha_Volkova [10]
2 years ago
6

Prove the following trigonometric identities

Mathematics
1 answer:
alexandr1967 [171]2 years ago
4 0

Answer:

Greetings !

check the attachment above☝️ but i haven't done the second question wait a moment. thx

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2800 - 4000

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The base of a solid is the region in the first quadrant between the graph of y=x2 and the x -axis for 0≤x≤1 . For the solid, eac
nata0808 [166]

Answer:

The volume of the solid is π/40 cubic units.

Step-by-step explanation:

Please refer to the graph below.

Recall that the area of a semi-circle is given by:

\displaystyle A=\frac{1}{2}\pi r^2

The volume of the solid will be the integral from <em>x</em> = 0 to <em>x</em> = 1 of area A. Since the diameter is given by <em>y</em>, then the radius is <em>y/2</em>. Hence, the volume of the solid is:

\displaystyle V=\int_0^1\frac{1}{2}\pi \left(\frac{y}{2}\right)^2\, dx

Substitute:

\displaystyle V=\frac{1}{2}\pi\int_0^1\left(\frac{x^2}{2}\right)^2\, dx

Simplify:

\displaystyle V=\frac{1}{2}\pi \int_0^1\frac{x^4}{4}\, dx

Integrate:

\displaystyle V=\frac{1}{2}\pi \left[\frac{x^5}{20}\Big|_0^1\right]

Evaluate:

\displaystyle V=\frac{\pi}{40}\left((1)^5-\left(0\right)^5\right)=\frac{\pi}{40}\text{ units}^3

The volume of the solid is π/40 cubic units.

4 0
3 years ago
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