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2 years ago

HELP PLEASE

Mathematics

1 answer:

kolbaska11 [484]2 years ago

4 0

Answer:

-4, -1, and 5

Step-by-step explanation:

1. The x-intercepts of a function is where the function intersects with the x-axis.

2. Given the information above, we can see that the function intersects the x-axis at (-4,0), (-1,0), and (5,0).

This means that the x-intercepts are -4, -1, and 5.

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Write an exponential function in the form y=ab^xy=ab

Zarrin [17]

Answer:

Step-by-step explanation:

$y=ab^x\\x=0,y=4\\4=ab^0\\4=a(1)\\a=4\\y=4b^x\\x=2,y=256\\256=4b^2\\b^2=\frac{256}{4} =64\\b=\pm8\\y=4(8)^x\\or\\y=4(-8)^x$

8 0

2 years ago

At 2 PM, a thermometer reading 80°F is taken outside where the air temperature is 20°F. At 2:03 PM, the temperature reading yiel

Alexeev081 [22]

Use Law of Cooling:
$T(t) = (T_0 - T_A)e^{-kt} +T_A$
T0 = initial temperature, TA = ambient or final temperature

First solve for k using given info, T(3) = 42
$42 = (80-20)e^{-3k} +20 \\ \\ e^{-3k} = \frac{22}{60}=\frac{11}{30} \\ \\ k = -\frac{1}{3} ln (\frac{11}{30})$

Substituting k back into cooling equation gives:
$T(t) = 60(\frac{11}{30})^{t/3} + 20$

At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:
$T(t) = (x-80)(\frac{11}{30})^{t/3} + 80 \\ \\ 71 = (x-80)(\frac{11}{30})^{\frac{10-t}{3}} + 80$
Solve for x:
$x = -9(\frac{11}{30})^{\frac{t-10}{3}} + 80$
Sub back into original cooling equation, x = T(t)
$-9(\frac{11}{30})^{\frac{t-10}{3}} + 80 = 60 (\frac{11}{30})^{t/3} +20$
Solve for t:
$60 (\frac{11}{30})^{t/3} +9(\frac{11}{30})^{\frac{-10}{3}}(\frac{11}{30})^{t/3} = 60 \\ \\ (\frac{11}{30})^{t/3} = \frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}} \\ \\ \\ t = 3(\frac{ln(\frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}})}{ln (\frac{11}{30})}) \\ \\ \\ t = 4.959$

This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM

8 0

3 years ago

Now complete the square for 2x^2 + 16x + 3.

o-na [289]

Answer:

To complete the square the equation would be 2(x+4)^2-29

4 0

3 years ago

Freeee poinnnnttttsssssss

EleoNora [17]

Heyy lol :) I’m bored as heck but yeah

3 0

2 years ago

Read 2 more answers

PLS HELP IM FAILING MATH!

oksano4ka [1.4K]

Answer:

1. Never true

2. Never true

3. Bad question! Typo? (see discussion below)

4. Always true

5. Always false

Step-by-step explanation:

1. x - 13 = x + 1. Subtract x from both sides of the equation, and you get -13 = 1. False! (Never true!)

2. x + 1/2 = x - 1/2. Subtract x from both sides: 1/2 = - 1/2. False! (Never true!)

3. This one's weird, with two equal signs. That's not unusual; multiple equal signs are often used when a chain of equalities is being displayed. For instance, you can write (3)(2x + 5) = (3)(2x) + (3)(5) = 6x + 15. That's an example of the Distributive Property--the 3 is multiplied by both of the terms inside parentheses (shown after the first equal sign), then actually doing those multiplications produces the expression after the second equal sign.

OK! This question says 2(x + 3) = 5x = 6 - 3x. Take it in two parts.

a. 2(x + 3) = 5x Distribute the 2.

2x + 6 = 5x Now subtract 2x from both sides.

6 = 3x Divide both sides by 3.

2 = x So that first part is true only when x = 2. Gaa! That's not one of your answer choices. Now, check out the second part

b. 5x = 6 - 3x Add 3x to both sides.

8x = 6 Divide by 8

x = 6/8 = 3/4

It doesn't help to use the first and <u>third</u> expressions, either.

2(x + 3) = 6 - 3x Distribute the 2

2x + 6 = 6 - 3x Add 3x.

5x + 6 = 6 Subtract 6.

5x = 0 Divide by 5

x = 0

None of these is always false. None of these is always true.

4. x - 3 = 2x - 3 - x Simplify the right side by combining the x terms.

x - 3 = x - 3 Aha! Same expression on both sides! Always true

5. 3(x - 5) = 2(x - 5) + x Distribute the 3. Distribute the 2.

3x - 15 = 2x - 10 + x Combine the x terms on the right.

3x - 15 = 3x - 10 Subtract 3x

-15 = -10 (Always false!)

7 0

2 years ago