3(x^2+6x+8)
3(x+4)(x+2)
The answer is D
Tan x /(1 +sec x) + (1+sec x) /tan x
Tan x=sin x / cos x
1+ sec x=1 +1/cos x=(cos x+1)/cos x
Therefore:
tan x /(1 +sec x) =(sin x/cos x)/(cos x+1)/cos x=
=(sin x * cos x) / [cos x* (cos x+1)]=sin x /(Cos x+1)
(1+sec x) /tan x=[(cos x+1)/cos x] / (sin x/cos x)=
=[cos x(cos x+1)]/(sin x *cos x)=(cos x+1)/sin x
tan x /(1 +sec x) + (1+sec x) /tan x=
=sin x /(Cos x+1) + (cos x+1)/sin x=
=(sin²x+cos²x+2 cos x+1) / [sin x(cos x+1)]=
Remember: sin²x+cos²x=1⇒ sin²x=1-cos²x
=(1-cos²x+cos²x+2 cos x+1) / [sin x(cos x+1)]=
=2 cos x+2 / [sin x(cos x+1)]=
=2(cos x+1) / [sin x(cos x+1)]=
=2 /sin x
Answer : tan x /(1 +sec x) + (1+sec x) /tan x= 2/sin x
Answer:
According to the given problems the one that gets closer is the first option. ^12sqrt27/2
Step-by-step explanation:
<em>Simplify the radical by breaking the radicand up into a product of known factors.</em>
The answer for the first question is 12
√
27
/ 2
Answer:
x=-1
Step-by-step explanation:
Answer:
<u>11t² + 7t + 3</u>
Step-by-step explanation:
⇒ (5t² + 4) - (6t² - 7t + 1)
⇒ 5t² + 4 - 6t² + 7t - 1
⇒ <u>11t² + 7t + 3</u>
