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kaheart [24]
3 years ago
12

Help someone!! Thank you!

Mathematics
2 answers:
zvonat [6]3 years ago
5 0
The answer is D. Which is 1.3
Margaret [11]3 years ago
4 0

Answer:

D. 1.3

Step-by-step explanation:

Perimeter (square) = 4*side

4 = 4*side

side = 1

We have triangle QVR. QV is a hypotenuse.

If we look at the triangle QTR, QT is a hypotenuse.

QV should be less than QT.

Let's find QT using Pythagorean theorem.

c² = a² + b²

QT² = QR² + RT² = 1² + 1² = 2

QT = √2 ≈ 1.4

QV < QT

QV < 1.4

We have 1.3 and 1 that are less than 1.4, but 1 is a length of a leg of the triangle, so 1 is impossible.

Answer D. 1.3

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Log (z ^ 3)/(x ^ 4 * y ^ 5) with steps please
Greeley [361]

Answer:

Step-by-step explanation:

5 0
3 years ago
evaluate if s equals 5 and 2 equals 7 3s^2 +t^2 -3 please show how you got your work I will get brainiest
iragen [17]

3 {(5)}^{2}  + ( {7)}^{2}  - 3 \\ 3(25) + 49 - 3 \\ 75 + 49 - 3 \\  = 121
6 0
3 years ago
For a school fundraiser mai will make school spirit bracelets. She will order bead wiring and alphabet beads to create the schoo
Andreas93 [3]

Answer:

235 bracelets

Step-by-step explanation:

Mai must spend $250 on wire and $5.30 per bracelet beads. Mai creates the expression.

We are given the equation:

5.3n+ 250 to represent the cost of making n bracelets.

The maximum number of bracelets Mai can make with a budget of $1500 Is calculated as:

$1500 = 5.3n+ 250

Collect like terms

1500 - 250 = 5.3n

1250 = 5.3n

n = 1250/5.3

n = 235.8490566 bracelets.

Bracelets are created as whole numbers and they can't be in decimal form.

Therefore, the maximum number of bracelets Mai can make with a budget of $1500 is 235 bracelets.

6 0
3 years ago
there are n counters in a bag. 4 of the counters are red and the rest are blue. Ross takes a counter from the bag at random and
Ainat [17]

Answer: n = 10.

Step-by-step explanation:

In the bag, we have n counters.

4 of the counters are red.

the rest are blue, then we have:

(n - 4) blue counters.

Now, the probability that Ross takes a blue counter from the bag is equal to the quotient between the number of blue counters (n - 4) and the total number of counters, n

Then the probability is:

p1 = (n - 4)/n

Now he draws another, and it must be blue again, then we can calculate the probability in the same way as above, but he already take a blue counter, so the number of blue counters is (n - 5) and the total number of counters is (n - 1)

The probability of this event is:

p2 = (n - 5)/(n - 1)

The joint probability (the probability that Ross takes two blue counters) is equal to the product of the individual probabilities, and we know that this is equal to 1/3, then we have the equation:

1/3 = ( (n - 4)/n)*((n - 5)/(n - 1))

Now let's solve this for n.

n*(n - 1)/3 = (n - 4)*(n - 5)

(n^2 - n)/3 = n^2 - 4*n - 5*n + 20

n^2 - n = 3*(n^2 - 9*n + 20)

n^2 - n = 3*n^2 - 27*n + 60

0 = (3*n^2 - n^2) - 27*n + n + 60

0 = 2*n^2 - 26*n + 60

The two solutions of this equation can be found with Bhaskara's equation:

n = \frac{-(-26) +- \sqrt{(-26)^2 - 4*2*60} }{2*2} = \frac{26+- 14}{4}

Then the two solutions are:

n = (26 - 14)/4 = 3

This is not an option, because we know for sure that we have 4 red counters, then this option can be discarded.

The other solution is:

n = (26 + 14)/4 = 40/4 = 10

Then we have n = 10, 10 counters in total.

4 0
3 years ago
A bag contains 3 red marbles, 4 blue marbles and 7 green marbles. If two marbles are drawn out of the bag, what is the probabili
bija089 [108]

Answer:

0.1428 if you round then it would be 0.143 2/14

Step-by-step explanation:

5 0
3 years ago
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