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1 year ago

Write an equation that passes through (4,-3) and is perpendicular to y=-2x-4

Mathematics

1 answer:

makkiz [27]1 year ago

5 0

The point is (4,-3) and is perpendicular to y=-2x-4.

The slope is given , m=-2.

For the perpendicular line, the slope is

$m_1\times m_2=-1$ $m_1\times-2=-1$ $m_1=\frac{1}{2}$

Now, then the general equation is

$y-y_1=m(x-x_1)$

Substitute the values.

$y-(-3)=\frac{1}{2}(x-4)$ $y+3=\frac{1}{2}(x-4)$ $y=\frac{1}{2}x-\frac{4}{2}-3$ $y=\frac{1}{2}x-2-3$ $y=\frac{1}{2}x-5$

Hence the equation is determined as

$y=\frac{1}{2}x-5$

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How would you write 8^5 as a multiplication expression? A. 8 × 5 B. 8 × 8 × 8 × 8 × 8 C. 5 × 5 × 5 × 5 × 5 × 5 × 5 × 5

Neporo4naja [7]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

if we ever face a number written in the form of $\underline{x^{n}}$ where x denotes the base and n denotes the exponent or power , we can expand it in the following way -

$x^{n} = x \times x \times x \times.... x ( upto\: " n " \: times )$

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4 0

2 years ago

Read 2 more answers

On which triangle can the law of cosines be applied once to find an unknown angle measure? Law of cosines: a2 = b2 + c2 – 2bccos

Maksim231197 [3]

Answer:

C) Angle X Y W is 76 degrees. The length of X Y is 5, the length of W Y is 10, and the length of W X is y.

Step-by-step explanation:

On which triangle can the law of cosines be applied once to find an unknown angle measure?

The Law of cosines is given as:

a² = b² + c² - 2bccos(A)

From the options given above, the correct option is Option C

C) Angle X Y W is 76 degrees. The length of X Y is 5, the length of W Y is 10, and the length of W X is y.

This is because:

Law of Cosines helps us to find an unknown side of a triangle when we are given 2 known sides and 1 angle.

In the above question, we are given angle 76 degree, and the length of two sides: The length of X Y is 5, the length of W Y is 10

The unknown side is the length of W X which is represented as y.

Hence, Option C is the correct option.

3 0

3 years ago

Read 2 more answers

Find the face value of the 20-year zero-coupon bond at 4.4%, compounded semiannually, with a price of $8,375.

umka21 [38]

Given:

Time,

t = 20 years

Rate,

r = 4.4%

Price

= $8,375

Now,

The yield will be:

= $\frac{4.4}{2}$

= $1.1$ (%)

Time will be:

= $20\times 2$

= $40 \ periods$

As we know the formula,

⇒ $Price \ of \ bond = \frac{Face \ value}{(1+\frac{r}{2} )^{n\times 2}}$

By substituting the values, we get

$8375=\frac{Face \ value}{(1+\frac{0.044}{2} )^{20\times 2}}$

$8375=\frac{Face \ value}{(1.022)^{40}}$

$8375=\frac{Face \ value}{2.3880083}$

The face value will be:

$Face \ value = 2.3880083\times 8375$

$=20,000$ ($)

Learn more about face value here:

brainly.com/question/14862802

5 0

3 years ago

Cost of a CD: $17.50 Markup: 45%

Marizza181 [45]

Answer:

25.375

Step-by-step explanation:

17.50×45%=7.875

17.50+7.875=25.375 new price

8 0

2 years ago

Which explains how to find the quotient of the division below? Negative 3 and one-third divided by StartFraction 4 over 9 EndFra

Ulleksa [173]

Answer:

(B) Write Negative 3 and one-third as Negative StartFraction 10 over 3 EndFraction, and find the reciprocal of StartFraction 4 over 9 EndFraction as StartFraction 9 over 4 EndFraction. Then, rewrite Negative 3 and one-third divided by StartFraction 4 over 9 EndFraction as Negative StartFraction 10 over 3 EndFraction times StartFraction 9 over 4 EndFraction. The quotient is Negative 7 and StartFraction 6 over 12 EndFraction = Negative 7 and one-half.

Step-by-step explanation:

To find the quotient of the division:

$-3\dfrac13 \div \dfrac49$