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dimaraw [331]
3 years ago
13

Alex is 4 years younger than 2 times his sister's age. Write a rule that represents Alex's age x as a function of his sister's a

ge y. How old is Alex, if his sister is 11?
Mathematics
2 answers:
sesenic [268]3 years ago
7 0

Answer:

alex is 18 sis is 11

Step-by-step explanation:

Vesna [10]3 years ago
6 0

Answer:

y = 2x - 4; Alex is 18.

Step-by-step explanation:

Since Alex is 4 years younger than 2 times his sister's age, and his sister is y and Alex is x, the function of y to x must be y = 2x - 4.

According to the rule, if Alex's sister is 11, Alex is 2 times that minus four. If you calculate that, you get

11 * 2 = 22

22 - 4 = 18

So Alex is 18 if his sister is 11.

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Cubed root x cubed root x2​
Yuki888 [10]

Answer:

Final answer is \sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x.

Step-by-step explanation:

Given problem is \sqrt[3]{x}\cdot\sqrt[3]{x^2}.

Now we need to simplify this problem.

\sqrt[3]{x}\cdot\sqrt[3]{x^2}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}

Apply formula

\sqrt[n]{x^p}\cdot\sqrt[n]{x^q}=\sqrt[n]{x^{p+q}}

so we get:

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{1+2}}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{3}}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x

Hence final answer is \sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x.

7 0
3 years ago
Prove: An even plus an even is<br> an even<br> 2n + 2m = [? ](n + m)<br> = even
KonstantinChe [14]

Answer:

2(n + m)

Step-by-step explanation:

3 0
2 years ago
A store is having a 20% off sale on all merchandise. If Mai buys one item and saves 13$, what was the original sale price of her
Montano1993 [528]

Answer:

$65 is the original price

Step-by-step explanation:

65 x .8 = 52 which is 13 off

4 0
2 years ago
Solve 3(x-5)-4(x+3)=​
Wittaler [7]

3(x-5)-4(x+3)

Multiply the first bracket by 3

(3)(x)=3x

(3)(-5)=-15

(-4)(x)=-4x

(-4)(3)=-12

3x-15-4x-12

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Answer: -x-27

5 0
2 years ago
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Answer:

300

Step-by-step explanation:

5x60

4 0
2 years ago
Read 2 more answers
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