Answer:
10.9 s
Explanation:
Given:
Δx = 367 m
v₀ = 0 m/s
a = 6.2 m/s²
Find: t
Δx = v₀ t + ½ at²
367 m = (0 m/s) t + ½ (6.2 m/s²) t²
t ≈ 10.9 s
Answer:
1.736m/s²
Explanation:
According to Newton's second law;

where;
Fm is the moving force = 70.0N
Ff is the frictional force acting on the body

is the coefficient of friction
m is the mass of the object
g is the acceleration due to gravity
a is the acceleration/deceleration
The equation becomes;

Substitute the given parameters

Hence the deceleration rate of the wagon as it is caught is 1.736m/s²
Are you answering a question or asking? You have already seemed to get the answer, A is the correct answer :I
Answer:
No
Explanation:
Some objects gain momentum.
(Hint: the time<span> to rise to the </span>peak<span>is one-half the </span>total hang-time<span>.).</span>