Answer:
The magnitude of the force that the 6.3 kg block exerts on the 4.3 kg block is approximately 41.9 N
Explanation:
Forces on block 4.3 kg are:
63N to the right and R21 (contact force from the 6.3 kg block) to the left
Net force on 4.3 kg block is: 63 N - R21
Forces on the 6.3 kg block are:
R12 to the right (contact force from the 4.3 kg block) and 11 N to the left.
So net force on the 6.3 kg block is: R12 - 11 N
According to the action-reaction principle the contact forces R21 and R12 must be equal in magnitude (let's call them simply "R").
Then, since the blocks are moving with the SAME acceleration, we equal their accelerations:
a1 = (63 N - R)/4.3 = (R - 11 N)/6.3 = a2
solve for R by cross multiplication
6.3 (63 - R) = 4.3 (R - 11)
396.9 - 6.3 R = 4.3 R - 47.3
369.9 + 47.3 = 10.6 R
444.2 = 10.6 R
R = 444.2 / 10.6
R = 41.90 N
By definition, centripetal acceleration is given by:
Where,
v: tangential disk speed
r: disk radius
Substituting values in the given equation we have:
Rounding the result we have:
Answer:
The centripetal acceleration of the disc edge in m/s^2 is:
HEAT flows from a warmer object to a cooler object until both objects are the same temperature. The answer is heat!
The final velocity is 3.47 m/s east
Explanation:
We can solve this problem by using the law of conservation of momentum. In fact, the total momentum of the two players before and after the collision must be conserved:
where:
is the mass of the first player
is the initial velocity of the first player (we take east as positive direction)
is the mass of the second player
is the initial velocity of the second player
is their final combined velocity after the collision
Re-arranging the equation and substituting the values, we find:
So, their velocity afterwards is 3.47 m/s east.
Learn more about momentum:
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