<h3>
Option A</h3>
In a Series circuit with two identical loads, the voltage across each load will be: the same
<h3><u>
Explanation:</u></h3>
A series circuit is one with total the loads in a row. There is barely ONE path for electricity to pass. If this circuit was a series of flashbulbs, and one left out, the left bulbs would switch off. T
he current in a series circuit is universally the same and the voltage over the circuit is the amount of the unique voltage drops over each component. The voltage referred to as a series circuit is equivalent to the amount of the individual voltage drops.
Answer:
- 3/5" = 12'
- 1 3/4" = 35'
- 1 1/4" = 25'
- 9/10" = 18'
- 2 13/20" = 53'
Explanation:
One number is wrong; they all lack units.
The basic ratio is 1" = 20', so you can divide feet by 20 to find inches.
- 3/5" = 12'
- 1 3/4" = 35'
- 1 1/4" = 25'
- 9/10" = 18'
- 2 13/20" = 53'
Perhaps you want decimal inches:
- 0.60" = 12'
- 1.75" = 35'
- 1.25" = 25'
- 0.90" = 18'
- 2.65" = 53'
Answer:
Algorith does not work.
Explanation:
One of the ways to obtain the Dekker Algorithm is through a change in the declaration, that is, a declaration that can be executed at the exact moment it leaves the critical section. This way it is possible that the statement,
turn = 1-i / * P0 sets turn to 1 and P1 sets turn 0 * /
It can be changed to,
turn = (turn +1) \% n / * n = number or processes * /
The result will allow to define if it works or not, that is, if it is greater than 2 the algorithm will not be able to work.
Given this consideration we can say that,
<em>- The dead lock does not occur, because the mutual is imposed (if a resource unit has been assigned to a process, then no other process can access that resource).</em>
<em>- There is the possibility of starving if the shift is established in a non-contentious process.</em>
Directly it can be concluded that there is a possibility of starvation so the algorithm could not work, despite the fact that mutual exclusion guarantees that a dead block does not occur.
