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madam [21]
3 years ago
5

How are eras different from decades?

Engineering
1 answer:
ivolga24 [154]3 years ago
5 0

Answer:

decades are 10 years, while eras do not have set periods of time

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if this light stays on after the initial startup of the vehicle it signals a warning that there is something wrong with the serv
NemiM [27]

Service brake system indicator is the warning that there is something wrong with the service brake system.  Hence option f is correct.

<h3>What is indicator?</h3>

Amber-colored indicator lights can be found at the front, back, and occasionally on the left and right sides of the vehicle. Whether you're turning left, right, or into oncoming traffic, you use your indicators to signal your planned change of direction.

When this light turns on, one of two things will happen. Either the parking brake is engaged or the hydraulic fluid (brake fluid) in the master cylinder is low. Your brakes are made up of a system of hydraulic oil-filled tubes called brake lines.

Thus, service brake system indicator is the warning that there is something wrong with the service brake system.  Hence option f is correct.

To learn more about indicator, refer to the link below:

brainly.com/question/28093573

#SPJ1

7 0
1 year ago
A vertical piston-cylinder assembly contains water. The piston has a mass of 2 kg and a diameter of 7 cm . Assume atmospheric pr
Step2247 [10]

Answer:

for a) F= 744.97 N

for a) F= 167.85 N

for a) F= 764.57 N

Explanation:

the pressure developed by the piston should be higher than the saturated vapor pressure of water for boiling point at T=120 to ensure boiling.

Then from steam tables

T= 120°C → P required=Pr= 198.67 kPa

then the pressure developed by the piston is

P = (m*g + F)/A

where m= mass of the piston ,g= gravity F= force required and A= area of the piston

then

Pr = P = (m*g + F)/A

F = Pr*A-m*g

since A= π/4*D²

F =π/4* Pr*D²-m*g

replacing values

F =π/4* Pr*D²-m*g = π/4*198.67  *10³Pa*(0.07m)² -2kg* 9.8m/s²

F= 744.97 N

b) for T₂=80°C → Pr₂=47.41 kPa

F₂ =π/4* Pr₂*D²-m*g = π/4*47.41*10³Pa*(0.07m)² -2kg* 9.8m/s²

F₂= 167.85 N

c) for m=0 (mass of the piston neglected) ,the force required is

F₃ =π/4*Pr*D² =  π/4*198.67 *10³Pa*(0.07m)²= 764.57 N

F₃ =764.57 N

4 0
3 years ago
By balancing information security and access, a completely secure information system can be created.A. TrueB. False
Inessa05 [86]

Answer: true

Explanation:

5 0
3 years ago
A magician claims that he/she has invented a novel, super-fantastic heat engine. This engine operates between two reservoirs of
Marysya12 [62]

Answer:

A) Not possible, B) Posible, C) Possible, D) Not possible.

Explanation:

The maximum theoretical efficiency for any thermal engine is defined by Carnot's cycle, whose energy efficiency (\eta), no unit, is expressed below:

\eta = 1-\frac{T_{L}}{T_{H}} (1)

Where:

T_{L} - Cold reservoir temperature, in Kelvin.

T_{H} - Hot reservoir temperature, in Kelvin.

If we know that T_{L} = 250\,K and T_{H} = 750\,K, then the maximum theoretical efficiency for the thermal engine is:

\eta = 1-\frac{T_{L}}{T_{H}}

\eta = 0.667

For real thermal engines, the following inequation is observed:

0 \le \eta_{r} \le \eta (2)

Where \eta_{r} is the efficiency of the real heat engine, no unit.

There are two possible criteria to determine if a given heat engine is real:

Efficiency

\eta_{r} = 1 - \frac{Q_{L}}{Q_{H}} (3)

Where:

Q_{L} - Heat rejected to the cold reservoir, in kilojoules.

Q_{H} - Heat received from the hot reservoir, in kilojoules.

Power output

W = Q_{H}-Q_{L} (4)

Where W is the power output, in kilojoules.

Now we proceed to verify each case:

A) Q_{H} = 900\,kJ, Q_{L} = 600\,kJ, W_{m} = 400\,kJ

\eta_{r} = 0.333

0 \le \eta_{r} \le \eta

W = 300\,kJ

W \ne W_{m}

This engine is not possible.

B) Q_{H} = 900\,kJ, Q_{L} = 500\,kJ, W_{m} = 400\,kJ

\eta_{r} = 0.444

0 \le \eta_{r} \le \eta

W = 400\,kJ

W = W_{m}

The engine is possible.

C) Q_{H} = 900\,kJ, Q_{L} = 300\,kJ, W_{m} = 600\,kJ

\eta_{r} = 0.667

0 \le \eta_{r} \le \eta

W = 600\,kJ

W = W_{m}

The engine is possible.

D) Q_{H} = 900\,kJ, Q_{L} = 100\,kJ, W_{m} = 800\,kJ

\eta_{r} = 0.889

\eta_{r} > \eta

W = 800\,kJ

W = W_{m}

The engine is possible.

7 0
2 years ago
An internal combustion engine in which air is compressed to a high enough pressure and temperature that combustion occurs when f
pashok25 [27]

Answer:

Spark

Explanation

The spark plug fires igniting the fuel. In diesel trucks the air is compressed until ignition.

3 0
1 year ago
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