Drag each label to the correct location on the table. Match to identify permanent and temporary structures.

A good visual lead is .... seconds from the front of the vehicle, focusing in the center of the path of travel. Searching 20 to

Tomtit [17]

A good visual lead is 20-30 seconds from the front of the vehicle, focusing in the center of the path of travel. Searching 20 to 30 seconds ahead, gives you time to assess within the next ..12-15 seconds, actions you may need to take to control an approaching risk.

Discussion:

Keeping eye focus centered in a path of travel at an interval of 20 to 30 seconds away from the vehicle is critical to gaining enough info. as possible in the driving scene. Good targeting sets up good sight lines for referencing and good peripheral fields for observing changes.

It is important to look ahead 12-15 seconds into your target area as one drives. Compromise. space by giving as much space to the greater of two hazards.

Read more on driving visual leads:

brainly.com/question/7067386

3 0

3 years ago

In fuel oil piping systems, all exterior above-grade fill piping shall be __________ when tanks are abandoned or removed.

castortr0y [4]

Answer:

Removed

Hope this Helps!

6 0

3 years ago

An uncharged capacitor is connected to a resistor and a battery. Choose what happens to current, potential difference and charge

Ilya [14]

Answer:

The charge on the plates will increase with time

The potential difference across the capacitor starts with zero and then increases gradually to a maximum value

The current through the circuit starts high and then drops exponentially

Explanation:

<u>Case : An uncharged capacitor is connected to a resistor and a battery in a closed circuit.</u>

The charge on the plates will increase with time

applying this equation : Q = $Q_{0} [ 1 - e^{\frac{-t}{RC} } ]$ as the value of (t) increases the value of Q increases i.e. charge on the plates

The potential difference across the capacitor starts with zero and then increases gradually to a maximum value

applying this equation : V = $V_{0} [ 1 - e^{\frac{-t}{RC} } ]$

The current through the circuit starts high and then drops exponentially

current : I = $I_{0} e^{\frac{-t}{RC} }$

6 0

3 years ago

A "type 30" brake chamber has a diaphragm diameter of 8" which gives it

Montano1993 [528]

The piston makes four strokes in the crankshaft makes two revolutions between combustion firings. The diameter of the piston, and the inside diameter of the cylinder, is called a bore, so the area of the head of the piston is pi times the diameter squared divided by four.

5 0

3 years ago

Dos capacitores de placas paralelas, idénticos, pero con la excepción de que uno tiene el doble de separación entre sus placas q

Charra [1.4K]

Las características de la capacitancia permiten encontrar los resultados para las diferentes preguntas

1) El capacitor con menor distancia entre las placas tiene mayor campo eléctrico.

2) El capacitor con menor distancia tiene mayor carga

3) El capacitor con menor distancia tiene mayor densidad de carga

Los capacitores son sistema que sirve para acumular carga, esa formado por placas conductoras separadas una distancia pequeña, la capacitancia es

$C = \frac{Q}{DV} = \frac{\epsilon_o A}{d}$