Answer:
151.4496
Step-by-step explanation:
it has not been rounded or anything that is the exact answer
Answer:
Step-by-step explanation:
<u>Vertical Throw</u>
It refers to a situation where an object is thrown verticaly upwards with some inicial speed v_o and let in free air (no friction) until it completes its movement up and finally returns to the very same point of lauch. The only acting force is gravity
The projectile formula is given as
where t is time in seconds, h is the height in feet and v is the speed in ft/sec
We are required to find the time t where h=120 ft, knowing
Rearranging
This is a second-degree equation which will be solved with the formula
Two solutions are obtained
Both solutions are possible because the ball actually is at 120 ft in its way up and then when going down
Answer:
C (-3/4)
Step-by-step explanation:
Decimal form is - 0.75
Answer:
<em>D. v equals the square root of quantity z times the sum of w plus z end quantity</em>
Step-by-step explanation:
We will use pythagoras theorem to solve this question. According to ΔABD, side AB is the hypotenuse of the triangle while AD and BD are the opposite and adjacent sides.
From ΔABD, v² = z² + y² ... 1
Also from ΔABC, side AC is the hypotenuse, AB and BC are the opposite and the adjacent side. Since AC = w+z, AB = v and AC = x, then;
AC² = AB²+BC²
(w+z)² = v²+x²
v² = (w+z)² - x² ... 2
Also, from ΔBCD, x² = y²+w²... 3
Substituting equation 3 into 2 will give;
v² = (w+z)² - x²
v² = (w+z)² - (y²+w²) ... 4
Equating 1 and 4
z²+y² = (w+z)² - (y²+w²)
z²+y² =w²+z²+2wz - (y²+w²)
z²+y² =w²+z²+2wz - y² - w²
z²+y² = z²+2wz - y²
2y² = 2wz
y² = wz ... 5
From equation 1; v² = z² + y²
substituting eqn 5 into 1;
v² = z²+wz
v = √z(w+z)
Hence the correct expression of v in words is 'v equals the square root of quantity z times the sum of w plus z end quantity'