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Rasek [7]
3 years ago
12

To find the number for c

Mathematics
2 answers:
kodGreya [7K]3 years ago
4 0
You use the Pythagorean theorem which is a^2+b^2=c^2

So....
.8^2+.6^2=c^2
.64+.36=c^2
1=c^2
1=c becaaue the square root of one is one
dexar [7]3 years ago
3 0
A) 6^2 + 8^2 = C^2
36 + 64 = 100
Square root of 100 = 10
B) .6^2 + .8^2 = C^2
.36 + .64 = 1
Square root of 1= 1
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Six more than a number equals two times the sum of one-half the number plus three. Is this statement true for only one number, a
babymother [125]

your answer would be all numbers

let me show you:

step 1) 6 more than 4 is 10

step 2) two times the sum of one-half the number plus three is 2*(2+3)

step 3) 2+3 is 5,and 5*2 is 10

step 4) compare the answers from steps 1 and 3,they are both 10


so your answer is ALL numbers


8 0
3 years ago
What's 2x + 54. Just lmk whenever
Sophie [7]

Answer:

It's 27

Step-by-step explanation:

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GuDViN [60]
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3 0
4 years ago
You have 8,640 grams of a radioactive kind of cesium. If its half-life is 30 years, how much
Vikki [24]

The mass of cesium left afer 120 years if the original mass of cesium is 8640 with an half-life of 30 years,  is 540 grams.

<h3>What is half-life?</h3>

This can be defined as the time taken for half the amount of a radioactive substance to decay.

To calculate the amount of cesium left after 120 years, we use the formua below.

Formula:

  • R' = R/(2^{T/t})............. Equation 1

Where:

  • R = Original amount of Cesium
  • R' = New amount of cesium
  • T = Total time
  • t = Half-life

From the question,

Given:

  • R = 8640
  • T = 120 years
  • t = 30 years

Substitute these values into equation 1

  • R' = 8640/(2^{120/30})
  • R' = 8640/2^{4}
  • R' = 8640/16
  • R' = 540 grams.

Hence, The mass of cesium left afer 120 years is 540 grams.

Learn more about half-life here: brainly.com/question/25750315

4 0
2 years ago
5. Miguel took 32 comic books to his friend's house. This is 40% of his total
AfilCa [17]
The correct answer is A) 80
8 0
3 years ago
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