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SOVA2 [1]
3 years ago
14

. Write a function called is_sorted that takes a list as a parameter and returns True if the list is sorted in ascending order a

nd False otherwise. Here, I want you to make use of the input function, where users could provide an input that would be the members of the list.

Computers and Technology
1 answer:
aalyn [17]3 years ago
8 0

Answer:

There are multiple ways to solve the given problem, I will be presenting the most simple and easy way of solving this problem in few lines of code.

Python code:

def is_sorted(user_list):

   return user_list == sorted(user_list)

user_list=input("Please enter a list: ")

user_list = user_list.split()

print(is_sorted(user_list))

print("Your list: ", user_list)

Explanation:

A function is_sorted is created which takes a list as input and using the sorted() function of python which returns true when the list is sorted in ascending order and returns false when the list is not sorted in ascending order.

Driver code includes getting input list from the user and using split() function to create a list separated by space then printing the output of is_sorted function and in the last printing the contents of that list.

Output:

Please enter a list: 1 3 6 9

True

Your list:  ['1', '3', '6', '9']

Please enter a list: 15 7  2 20

False

Your list:  ['15', '7', '2', '20']

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List 5 differences between monitors and printers​
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A nursing informatics specialist is preparing an in-service program for staff on healthcare informatics and information technolo
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Answer:

A- information

Explanation:

According to my research on nursing informatics specialists, I can say that based on the information provided within the question the nurse would emphasize information as the primary focus. This is because knowing what healthcare informatics entails as well as having the knowledge of how to use the technology is the most important aspect of the job.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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In this lab, you use the flowchart and pseudocode found in the figures below to add code to a partially created C++ program. Whe
never [62]

Answer:

The equivalent program in C++:

#include<iostream>

#include <sstream>

using namespace std;

int main(){

   string Score, Rank;

   cout<<"Enter student score and class rank: ";

   cin>>Score>>Rank;

   int testScore = 0, classRank = 0;

   stringstream sstream(Score);

   sstream>>testScore;

   

   stringstream tream(Rank);

   tream>>classRank;

   

   if (testScore >= 90){

       if(classRank >=25){cout<<"Accept";}

       else{cout<<"Reject";}

   }

   else if(testScore >= 80){

       if(classRank >=50){cout<<"Accept";}

       else{cout<<"Reject";}

   }

   else if(testScore >= 70){

       if(classRank >=75){cout<<"Accept";}

       else{cout<<"Reject";}

   }

   else{cout<<"Reject";}

   return 0;

}

Explanation:

This declares Score and Rank as string variables

   string Score, Rank;

This prompts the user for score and class rank

   cout<<"Enter student score and class rank: ";

This gets the user input

   cin>>Score>>Rank;

This declarees testScore and classRank as integer; and also initializes them to 0

   int testScore = 0, classRank = 0;

The following converts string Score to integer testScore

<em>    stringstream sstream(Score);</em>

<em>    sstream>>testScore;</em>

The following converts string Rank to integer classRank

   stringstream tream(Rank);

   tream>>classRank;

The following conditions implement the conditions as given in the question.    

If testScore >= 90

<em>    if (testScore >= 90){</em>

If classRank >=25

<em>        if(classRank >=25){cout<<"Accept";}</em>

If otherwise

<em>        else{cout<<"Reject";}</em>

<em>    } ---</em>

If testScore >= 80

<em>    else if(testScore >= 80){</em>

If classRank >=50

<em>        if(classRank >=50){cout<<"Accept";}</em>

If otherwise

<em>        else{cout<<"Reject";}</em>

<em>    }</em>

If testScore >= 70

<em>    else if(testScore >= 70){</em>

If classRank >=75

<em>        if(classRank >=75){cout<<"Accept";}</em>

If otherwise

<em>        else{cout<<"Reject";}</em>

<em>    }</em>

For testScore less than 70

<em>    else{cout<<"Reject";}</em>

<em />

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Explanation:

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