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Alex Ar [27]
3 years ago
11

Jason jumped off of a cliff into the ocean in Acapulco while vacationing with some friends. His height above ocean measured in f

eet as a function of time could be modeled by the h(t) = -16t2 + 16t + 480, where t is the time in seconds from jumping off. How high is the cliff in feet?
Mathematics
1 answer:
lbvjy [14]3 years ago
8 0

Answer:

480 feet.

Step-by-step explanation:

We are told that the function h(t)=-16t^2+16t+480 models Jason's height above ocean measured in feet as a function of time and t is the time in seconds from jumping off.

To find the height of cliff we need to substitute t=0 in our given function as at t=0 we will get Jason's height above ocean which is same as the height of the cliff.

Upon substituting t=0 in our function we will get,

h(0)=-16(0)^2+16*0+480

h(0)=-0+0+480

h(0)=480

Since, the function gives Jason's height above ocean in feet, therefore, the cliff was 480 feet high.

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3 years ago
Assume that T is a linear transformation. Find the standard matrix of T. T: R^3 right arrow R^2 , T(e 1) =(1,2), and T(e2 ) =( -
irina [24]

Answer:

A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]

Step-by-step explanation:

Given

T:R^3->R^2

T(e_1) = (1,2)

T(e_2) = (-4,6)

T(e_3) = (2,-6)

Required

Find the standard matrix

The standard matrix (A) is given by

Ax = T(x)

Where

T(x) = [T(e_1)\ T(e_2)\ T(e_3)]\left[\begin{array}{c}x_1&x_2&x_3\\-&&x_n\end{array}\right]

Ax = T(x) becomes

Ax = [T(e_1)\ T(e_2)\ T(e_3)]\left[\begin{array}{c}x_1&x_2&x_3\\-&&x_n\end{array}\right]

The x on both sides cancel out; and, we're left with:

A = [T(e_1)\ T(e_2)\ T(e_3)]

Recall that:

T(e_1) = (1,2)

T(e_2) = (-4,6)

T(e_3) = (2,-6)

In matrix:

(a,b) is represented as: \left[\begin{array}{c}a\\b\end{array}\right]

So:

T(e_1) = (1,2) = \left[\begin{array}{c}1\\2\end{array}\right]

T(e_2) = (-4,6)=\left[\begin{array}{c}-4\\6\end{array}\right]

T(e_3) = (2,-6)=\left[\begin{array}{c}2\\-6\end{array}\right]

Substitute the above expressions in A = [T(e_1)\ T(e_2)\ T(e_3)]

A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]

Hence, the standard of the matrix A is:

A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]

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Answer:

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Step-by-step explanation:

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Answer:

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