Option D:
ΔCAN ≅ ΔWNA by SAS congruence rule.
Solution:
Given data:
m∠CNA = m∠WAN and CN = WA
To prove that ΔCAN ≅ ΔWNA:
In ΔCAN and ΔWNA,
CN = WA (given side)
∠CNA = ∠WAN (given angle)
NA = NA (reflexive side)
Therefore, ΔCAN ≅ ΔWNA by SAS congruence rule.
Hence option D is the correct answer.
Answer:
112-7v
Step-by-step explanation:
The graph will cross at the coordinates (-2, 9)
<h3>How to solve equations?</h3>
y = 3x + 15
y = 3 - 3x
y = 3x + 15
Hence,
when x = 2
y = 3(2) + 15 = 21
when x = 0
y = 3(0) + 15 = 15
y = 3 - 3x
when x = 2
y = 3 - 3(2)
y = 3 - 6
y = -3
when x = 0
y = 3 - 3(0)
y = 3
Therefore, let's check if the equation will cross.
y = 3x + 15
y = 3 - 3x
using substitution,
3 - 3x = 3x + 15
3 - 15 = 3x + 3x
- 12 = 6x
x = -12 / 6
x = -2
y = 3 - 3(-2)
y = 3 + 6
y = 9
Therefore, the graph will cross at the coordinates (-2, 9)
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Answer:
x=8
Step-by-step explanation:
solve the rational equation by combining expressions and isolating the variable x
