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3 years ago

PLEASE HELP!!!!!! ILL GIVE BRAINLIST

Mathematics

1 answer:

WITCHER [35]3 years ago

7 0

Answer:

16/5 or 3 1/5 mile

Step-by-step explanation:

Because he is traveling at a same rate, 4/5*4= 16/5.

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A girl throws a 2 kg rock with a net force of 6 N. What is the acceleration of the rock?

krek1111 [17]

Answer:
acceleration = 3 m/s²

Explanation:
From Newton's second law:
Force = mass * acceleration
We are given that:
Force = 6 Newton
mass = 2 kg

Substitute with the givens in the above equation to get the acceleration as follows:
Force = mass * acceleration
6 = 2 * acceleration
acceleration = 6 / 2 = 3 m/s²

Hope this helps :)

8 0

3 years ago

How do you simplify this

kramer

Answer:

multiply the bottom and the top by route 2 minus route 3

this gives 4 route 2 minus route 18 over minus 1

this gives minus 4 route 2 add route 18

route 18 simplifies to 3 route 2

minus 4 route 2 add 3 route 2 gives minus route 2 as the answer

3 0

3 years ago

I don't get the problem

Ulleksa [173]

A(b + c) = a*(b + c) = a*b + a*c

You must multiply individual terms and see what it would equal

3 0

3 years ago

Match each set of vertices with the type of triangle they form.

Andrew [12]

Answer: The calculations are done below.

Step-by-step explanation:

(i) Let the vertices be A(2,0), B(3,2) and C(5,1). Then,

$AB=\sqrt{(2-3)^2+(0-2)^2}=\sqrt{5},\\\\BC=\sqrt{(3-5)^2+(2-1)^2}=\sqrt{5},\\\\CA=\sqrt{(5-2)^2+(1-0)^2}=\sqrt{10}.$

Since, AB = BC and AB² + BC² = CA², so triangle ABC here will be an isosceles right-angled triangle.

(ii) Let the vertices be A(4,2), B(6,2) and C(5,3.73). Then,

$AB=\sqrt{(4-6)^2+(2-2)^2}=\sqrt{4}=2,\\\\BC=\sqrt{(6-5)^2+(2-3.73)^2}=\sqrt{14.3729},\\\\CA=\sqrt{(5-4)^2+(3.73-2)^2}=\sqrt{14.3729}.$

Since, BC = CA, so the triangle ABC will be an isosceles triangle.

(iii) Let the vertices be A(-5,2), B(-4,4) and C(-2,2). Then,

$AB=\sqrt{(-5+4)^2+(2-4)^2}=\sqrt{5},\\\\BC=\sqrt{(-4+2)^2+(4-2)^2}=\sqrt{8},\\\\CA=\sqrt{(-2+5)^2+(2-2)^2}=\sqrt{9}.$

Since, AB ≠ BC ≠ CA, so this will be an acute scalene triangle, because all the angles are acute.

(iv) Let the vertices be A(-3,1), B(-3,4) and C(-1,1). Then,

$AB=\sqrt{(-3+3)^2+(1-4)^2}=\sqrt{9}=3,\\\\BC=\sqrt{(-3+1)^2+(4-1)^2}=\sqrt{13},\\\\CA=\sqrt{(-1+3)^2+(1-1)^2}=\sqrt 4.$

Since AB² + CA² = BC², so this will be a right angled triangle.

(v) Let the vertices be A(-4,2), B(-2,4) and C(-1,4). Then,

$AB=\sqrt{(-4+2)^2+(2-4)^2}=\sqrt{8},\\\\BC=\sqrt{(-2+1)^2+(4-4)^2}=\sqrt{1}=1,\\\\CA=\sqrt{(-1+4)^2+(4-2)^2}=\sqrt{13}.$

Since AB ≠ BC ≠ CA, and so this will be an obtuse scalene triangle, because one angle that is opposite to CA will be obtuse.

Thus, the match is done.

4 0

3 years ago

Read 2 more answers

5(3-6x)=4(3x+7)+5x<br> solve the following equation

kherson [118]

5(3-6x)=4(3x+7)+5x
x= - 13/47

7 0

3 years ago

Read 2 more answers