Answer:
steps below
Step-by-step explanation:
3.2.1 AD = DB* sin 2 = DB * sin θ .. DE // AB ∠2= θ ... (1)
By laws of sines: DB / sin ∠5 = x / sin ∠4
∠4 = θ-α ∠5 = 180°-<u>∠1</u>-∠4 = 180°-<u>∠3</u>-∠4 = 180°-(90°-θ)-(θ-α)) = 90°+α
DB = (x*sin ∠5)/sin (θ-α)
= (x* sin (90°+α)) / sin (θ-α)
AD = DB*sinθ
= (x* sin (90°+α))*sinθ / sin (θ-α)
= x* (sin90°cosα+cos90°sinα)*sinθ / sin (θ-α) .... sin90°=1, cos90°=0
= x* cosα* sinθ / sin (θ-α)
3.2.2 Please apply Laws of sines to calculate the length
Answer:
Step-by-step explanation:
Answer:
127/4 or 31 3/4 or 31.75
Step-by-step explanation:
got this by dividing 254 with 6 3/4
Answer:
THATS MADDDD CAPPPP U NEED 25 POINTS OF THE QUESTION FOR BRAINLIEST
Answer:
Ribbon can't be enough
Step-by-step explanation:
Markin is making a flag shaped like a square. Each side measures 13 m. He wants to add ribbon along the edges. He has 48 m of ribbon. Does he have enough ribbon? If it is not enough,how much more ribbon needed?
Given :
Side length of square shaped flag = 13 m
Length of ribbon markin has to add along edges = 48 m
To know if the ribbon will enough ; we obtain the perimeter of the square shaped flag ;
4 * side length
4 * 13 = 52 meters
52 > 48
Since the perimeter is greater than the length of ribbon, then ribbon can't be enough
