Answer:
1890, total cost of lights per week
Step-by-step explanation:
The lights cost 45 dollars per bulb and 6 go out per day, 45×6=270
270 is the cost to replace the bulbs of one day.
270×7=1890. 1890 is the cost for a whole weeks worth of replacing these bulbs.
Answer:
308[cos(45) + isin(45)]
Step-by-step explanation:
z1×z2:
Modulus: r1 × r2
= 7×44 = 308
Argument: theta1 + theta2
= -70 + 115 = 45
z1z2 = 308[cos(45) + isin(45)]
Or
z1z2 = 154sqrt(2) + (i)154sqrt(2)
sqrt: square root
Answer:
10=y/11-13
We move all terms to the left:
-10-(y/11-13)=0
-y/11+13-10=0
We multiply all the terms by the denominator
-y+13*11-10*11=0
We add all the numbers together, and all the variables
-1y+33=0
We move all terms containing y to the left, all other terms to the right
-y=-33
y=-33/-1
y=+33
(y^5-1)(y^5+8)............
