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Alik [6]
2 years ago
6

PLEASE HELP I REALLY WOULD APPRECIATE IT!!!

Mathematics
1 answer:
liubo4ka [24]2 years ago
8 0
4083750 wish you luck on your assignment ~ JyMarkus
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What is x equal to in the equation 10+x=5(1/5x+2)
iren [92.7K]

Answer:

30

Step-by-step explanation:

Theorm

6 0
3 years ago
If 62% of 80 classmates like hip-hop, but 70% of 60 relatives like hip-hop, which one is more?
SIZIF [17.4K]

62 percent of 80 is more

Step-by-step explanation:

the 62 percent of 80 comes out to 49.6 people and the other one comes out to 42 people

i dont know how to explain how to do it

8 0
2 years ago
Read 2 more answers
6.) The line that passes through point (-2,3) and (6,y) has a slope of. What is the value of “y,?
WITCHER [35]
What is the slope? We need the slope to find y
7 0
3 years ago
In the figure, Δ ABC Δ XYZ. What is the perimeter of ΔABC? Show your work.
slava [35]

Answer:

49

Step-by-step explanation:

∆ABC~ ∆XYZ

AB= 11 that is half of XY = 22

therefore XZ/2 = AC (base) = 32/2 = 16

and YZ /2 = BC(hypotenuse) = 44/2 = 22

(a= 11, b= 16, c= 22)

perimeter of a triangle

P = a+b+c

P= 11+16+22= 49

8 0
3 years ago
The indefinite integral can be found in more than one way. First use the substitution method to find the indefinite integral. Th
Fantom [35]

Answer:

∫6x^5(x^6-2)\,dx = \frac{1}{2}(x^6-2)^2+C

Step-by-step explanation:

To find:

∫6x^5(x^6-2)\,dx

Solution:

Method of substitution:

Let x^6-2=t

Differentiate both sides with respect to t

6x^5\,dx=dt

[use (x^n)'=nx^{n-1}]

So,

∫6x^5(x^6-2)\,dx = ∫ t\,dt = \frac{t^2}{2}+C_1 where C_1 is a variable.

(Use ∫t^n\,dt=\frac{t^{n+1} }{n+1} )

Put t=x^6-2

∫6x^5(x^6-2)\,dx = \frac{1}{2}(x^6-2)^2+C_1

Use (a-b)^2=a^2+b^2-2ab

So,

∫6x^5(x^6-2)\,dx = \frac{1}{2}(x^6-2)^2+C_1=\frac{1}{2}(x^{12}+4-4x^6)+C_1=\frac{x^{12} }{2}-2x^6+2+C_1=\frac{x^{12} }{2}-2x^6+C

where C=2+C_1

Without using substitution:

∫6x^5(x^6-2)\,dx = ∫6x^{11}-12x^5\,dx = \frac{6x^{12} }{12}-\frac{12x^6}{6}+C=\frac{x^{12} }{2}-2x^6+C

So, same answer is obtained in both the cases.

7 0
3 years ago
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