PLEASE HELP I REALLY WOULD APPRECIATE IT!!!

Mathematics

1 answer:

liubo4ka [24]2 years ago

8 0

4083750 wish you luck on your assignment ~ JyMarkus

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Stephen was helping make party bags for his little brother’s party. They have to make a total of 10 party bags. They had 34 toy

Taya2010 [7]

A) Each child will receive 3 cars and 4 cars will be left over.

8 0

3 years ago

Triangle ΔABC has side lengths of a = 18, <img src="https://tex.z-dn.net/?f=b%3D18%5Csqrt%7B3%7D" id="TexFormula1" title="b=18\s

ozzi

The measure of angle A is 30 degree, the value of tan A is 1/√3 and the area of triangle ABC is 280.6 squared inches.

<h3 /><h3>What is the law of cosine?</h3>

When the three sides of a triangle is known, then to find any angle, the law of cosine is used.

It can be given as,

$\angle A=\cos^{-1}\left(\dfrac{b^2+c^2-a^2}{2bc}\right) \\\angle B=\cos^{-1}\left(\dfrac{a^2+c^2-b^2}{2ac}\right) \\\angle C=\cos^{-1}\left(\dfrac{a^2+b^2-c^2}{2ab}\right)$

Here, a,b and c are the sides of the triangle and A,B and C are the angles of the triangle.

Triangle ΔABC has side lengths of a = 18, b=18√3 and c = 36 inches.

Part A: Determine the measure of angle A

Put the value, in the cosine law, the measure of angle A.

$\angle A=\cos^{-1}\left(\dfrac{b^2+c^2-a^2}{2bc}\right) \\\angle A=\cos^{-1}\left(\dfrac{(18\sqrt{3})^2+36^2-18^2}{2(18\sqrt{3})(36)}\right) \\\angle A=0.5236\rm\; rad\\\angle A=30^o\rm\; degree\\$