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3 years ago

Hey can someone tell me why 132 is wrong? and help me with the right answer pls

Mathematics

1 answer:

andreev551 [17]3 years ago

4 0

Answer:

∠CBA = 132

Step-by-step explanation:

Bisectors split up an angle into two identical angles

Thus, 7x - 11 = 2x + 44

This is the equation we will use to solve for x

7x - 11 = 2x + 44

step 1 add 44 to each side

44 + 11 = 55

-11 + 11 cancels out

we now have 7x = 2x + 55

step 2 subtract 2x from each side

7x - 2x = 5x

2x - 2x cancels out

we now have 5x = 55

step 3 divide each side by 5

5x / 5 = x

55 / 5 = 11

we're left with x = 11

The question is asking for the measure of ∠CBA

To find the measure of ∠CBA we plug in 11 for x in one of the given expressions and multiply that by 2 ( this is because the two angles are identical so there is no need to find the measures of both because ∠CBD≅∠ABD )

7(11) - 11

7 * 11 = 77

77 - 11 = 66

66 * 2 = 132

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2 years ago

Select the postulate that is illustrated for the real numbers. 3x + 3 = 3(x + 1) The commutative postulate for multiplication Mu

fredd [130]

Distributive postulate.

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2 years ago

Dont really understand how to do this

bija089 [108]

Answers:

$t_{10} = -22 \ \text{ and } S_{10} = -85$

========================================================

Explanation:

$t_1 = \text{first term} = 5\\t_2 = \text{first term}-3 = t_1 - 3 = 5-3 = 2$

Note we subtract 3 off the previous term (t1) to get the next term (t2). Each new successive term is found this way

$t_3 = t_2 - 3 = 2-3 = -1\\t_4 = t_3 - 3 = -1-3 = -4$

and so on. This process may take a while to reach $t_{10}$

There's a shortcut. The nth term of any arithmetic sequence is

$t_n = t_1+d(n-1)$

We plug in $t_1 = 5 \text{ and } d = -3$ and simplify

$t_n = t_1+d(n-1)\\t_n = 5+(-3)(n-1)\\t_n = 5-3n+3\\t_n = -3n+8$

Then we can plug in various positive whole numbers for n to find the corresponding $t_n$ value. For example, plug in n = 2

$t_n = -3n+8\\t_2 = -3*2+8\\t_2 = -6+8\\t_2 = 2$

which matches with the second term we found earlier. And,

$tn = -3n+8\\t_{10} = -3*10+8\\t_{10} = -30+8\\t_{10} = \boldsymbol{-22} \ \textbf{ is the tenth term}$

---------------------

The notation $S_{10}$ refers to the sum of the first ten terms $t_1, t_2, \ldots, t_9, t_{10}$

We could use either the long way or the shortcut above to find all $t_1$ through $t_{10}$ . Then add those values up. Or we can take this shortcut below.

$Sn = \text{sum of the first n terms of an arithmetic sequence}\\S_n = (n/2)*(t_1+t_n)\\S_{10} = (10/2)*(t_1+t_{10})\\S_{10} = (10/2)*(5-22)\\S_{10} = 5*(-17)\\\boldsymbol{S_{10} = -85}$