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ipn [44]
3 years ago
14

Hey can someone tell me why 132 is wrong? and help me with the right answer pls

Mathematics
1 answer:
andreev551 [17]3 years ago
4 0

Answer:

∠CBA = 132

Step-by-step explanation:

Bisectors split up an angle into two identical angles

Thus, 7x - 11 = 2x + 44

This is the equation we will use to solve for x

7x - 11 = 2x + 44

step 1 add 44 to each side

44 + 11 = 55

-11 + 11 cancels out

we now have 7x = 2x + 55

step 2 subtract 2x from each side

7x - 2x = 5x

2x - 2x cancels out

we now have 5x = 55

step 3 divide each side by 5

5x / 5  = x

55 / 5 = 11

we're left with x = 11

The question is asking for the measure of ∠CBA

To find the measure of ∠CBA we plug in 11 for x in one of the given expressions and multiply that by 2 ( this is because the two angles are identical so there is no need to find the measures of both because ∠CBD≅∠ABD )

7(11) - 11

7 * 11 = 77

77 - 11 = 66

66 * 2 = 132

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Step-by-step explanation:

In order to find the max height the ball reached, we have to complete the square on that quadratic. That will also, conveniently so, give us the number of seconds it will take the ball to reach that max height, that answer to part b. Let's begin to complete the square. Normally, you would move the constant over to the other side of the equals sign, but there is no constant here. The next step is to get the leading coefficient to be a 1, and ours right now is a -15. So we have to factor it out. Here's where we start the process of completing the square.

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-15(t^2-\frac{20}{3}t+\frac{400}{36})=0+??? Because this is an equation, what we add to the left side also has to be added to the right. BUT we didn't just add in 400/36, because we have that -15 out front as a multiplier that refuses to be ignored. What we actually added in was -15(400/36):

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The answer to a. is vound in the second number of our vertex: k, the max height. The max of the golf ball was 500/3 feet or 166 2/3 feet.

Part b is found in the first number of the vertex: h, the number of seconds it took the golf ball to reach that max height. The time it took was 3 1/3 seconds.

Part c. is to state the domain (the time) and the range (the height) of the ball.

Domain is

D: {x | 0 ≤ x ≤ 3 1/3} and

Range is

R: {y | 0 ≤ y ≤ 166 2/3}

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