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SOVA2 [1]
3 years ago
6

nathan smiled at 50 people one day and recorded that 36 people smiled back at him.Based on his observations how many people shou

ld nathan expect to return a smile if he smiles at 650 people over a period of time
Mathematics
1 answer:
Olegator [25]3 years ago
4 0

Given :

Nathan smiled at 50 people one day and recorded that 36 people smiled back at him.

To Find :

How many people should Nathan expect to return a smile if he smiles at 650 people over a period of time.

Solution :

Ratio of people smiled by total number of people is :

R = \dfrac{36}{50}

Now, it is given that we have to use the given conditions.

Therefore, ratio will be same :

\dfrac{s}{650}=\dfrac{36}{50}\\\\s = \dfrac{36}{50}\times 650\\\\s = 468

Therefore, number of smiles Nathan expect to return is 468.

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8a^3 b^8+4ab^5-16ab^8= <br> need help plz! (factor completely)
lakkis [162]
We can factor out the 4 to get
4(2a^3b^8+ab-4ab^8)
we can also factor out the ab
4ab(2a^2b^7+1-4b^7)
that is factored completely
6 0
3 years ago
Which ordered pair is the solution to the system of equations?
kozerog [31]
The answer and process is shown in the following picture

8 0
2 years ago
Given the set points K+1:(-1,8),(1,0) and (2,5), find the quadratic polynomial interpolate
Sauron [17]

Answer:

The interpolating polynomial is p(x) = 1-4x+3x^2.

Step-by-step explanation:

We want to find a quadratic polynomial p(x) such that p(-1)=8, p(1)=0 and p(2)=5. In order to do this let us write p(x) = a_0+a_1x+a_3x^2.

Now, evaluating the polynomial in the points -1, 1 and 2 we get

\begin{cases} 8 = p(-1) &= a_0-a_1+a_2\\ 0 = p(1) &= a_0+a_1+a_2\\ 5 = p(2) &= a_0+2a_1+4a_2\end{cases}

This relations give us a linear system of equations:

\begin{cases} 8 &= a_0-a_1+a_2\\ 0 &= a_0+a_1+a_2\\ 5&= a_0+2a_1+4a_2\end{cases}

where the a_0, a_1 and a_2 are the unknowns.

The augmented matrix of the system is

\begin{pmatrix}1 & -1 & 1 & 8\\ 1 & 1 & 1 & 0\\ 1 & 2 & 4 & 5\end{pmatrix}

In this matrix it is easy to eliminate the 1's of the first column and get

\begin{pmatrix} 1 & -1 & 1 & 8\\ 0 & 2 & 0 & -8\\ 0 & 3 & 3 & -3\end{pmatrix}

From this matrix we can find the values of each unknown. Notice that the second row gives us 2a_2=-8 that yields a_1=-4.

Then, the third row means 3a_1+3a_2=-3 that gives -12+3a_2=-3. So, a_2=3.

Finally, the first row is a_0-a_1+a_2=8 and substituting is a_0+7=8 that yields a_0=1.

Therefore, the interpolating polynomial is

p(x) = 1-4x+3x^2.

8 0
3 years ago
HELPPPPPPPPPPPPPPPPPPPPPP
AlexFokin [52]

Answer:

A. x= 3, y= -2

Step-by-step explanation:

[2] 2x= 4y+14

[1] 3y+5x=9

Solve equation [2] for the variable  x

 [2]    2x = 4y + 14

 [2]    x = 2y + 7

// Plug this in for variable  x  in equation [1]

  [1]    5•(2y+7) + 3y = 9

  [1]    13y = -26

// Solve equation [1] for the variable  y

  [1]    13y = - 26

  [1]    y = - 2

// By now we know this much :

   x = 2y+7

   y = -2

// Use the  y  value to solve for  x

   x = 2(-2)+7 = 3

good luck, I hope this helps!!!

5 0
2 years ago
when solving the equation 5x-3=5, MaReeco rewrote the equation as 5x =2.Did MaReeco perform an acceptable move to this equation?
aliina [53]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the equation

5x-3=5

MaReeco's rewrote equation is given by

5x = 2

As MaReeco subtracted 3 to the right side of the equation, which imbalanced the equation. Hence, it is not correct.

Correction:

For the next step, MaReeco should have added 3 to both sides

i.e.

5x-3+3=5+3

5x=8

Therefore, the acceptable move would have been:

  • 5x=8
6 0
2 years ago
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