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VikaD [51]
3 years ago
5

What is 9^3 as a power of 3 ​

Mathematics
2 answers:
Alex787 [66]3 years ago
4 0

Answer:

729

Step-by-step explanation:

9³ you just type that in the calculator

maw [93]3 years ago
4 0

Answer:

{3}^{6}

Step-by-step explanation:

\huge {9}^{3}  \\  \huge= ( {3}^{2} )^{3}  \\  \huge = {3}^{2 \times 3}  \\  \huge= {3}^{6}

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Three out of four students at middle school ride the bus if there are 640 students at middle school how many students ride the b
lina2011 [118]
309 because 400-91=309
4 0
3 years ago
∆ABC is translated 6 units up and 3 units left to create ∆A'B'C'.
guapka [62]
The correct answer is 1

4 0
3 years ago
I need help with this math problem?
Nuetrik [128]

Answer:

401.92u^3

Step-by-step explanation:

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(3.14*4^2)*8=401.92

3 0
3 years ago
Prove that sin^4x + cos^4x= sinxcosx
yKpoI14uk [10]

Answer:

(the relation you wrote is not correct, there may be something missing, so I will simplify the initial expression)

Here we have the equation:

sin^4(x) + cos^4(x)

We can rewrite this as:

(sin^2(x))^2 + (cos^2(x))^2

Now we can add and subtract cos^2(x)*sin^2(x) to get:

(sin^2(x))^2 + (cos^2(x))^2 + 2*cos^2(x)*sin^2(x) - 2*cos^2(x)*sin^2(x)

We can complete squares to get:

(cos^2(x) + sin^2(x))^2 - 2*cos(x)^2*sin(x)^2

and we know that:

cos^2(x) + sin^2(x) = 1

then:

1 - 2*sin(x)^2*cos(x)^2

This is the closest expression to what you wrote.

We also know that:

sin(x)*cos(x) = (1/2)*sin(2*x)

If we replace that, we get:

1 - \frac{sin^2(2*x)}{2}

Then the simplification is:

cos^4(x) + sin^4(x)  = 1 - \frac{sin^2(2*x)}{2}

7 0
3 years ago
What number is the dividend in the division problem below?
Paha777 [63]

Answer:

30 = 6×5

The dividend is 30.

:)

6 0
3 years ago
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