Answer:
no. because they are bot equivalent ratios or proportions
Answer:
<h2>Option B is the right answer.</h2>
Step-by-step explanation:
are two irrational numbers, that is, they can not be shown as the fraction of two integers.
is also a irrational number, since it also can not be represented as the fraction of integers.
Hence, the given expression represent the product of two irrational number and is equivalent to an irrational number.
<span>the particle's initial position is at t=0, x = 0 - 0 + 4 = 4m
velocity is rate of change of displacement = dx/dt = d(t^3 - 9t^2 +4)/dt
= 3t^2 - 18t
acceleration is rate of change of velocity = d(3t^2 -18t)/dt
= 6t - 18
</span><span>the particle is stationary when velocity = 0, so 3t^2 - 18t =0
</span>3t*(t - 6) = 0
t = 0 or t = 6s
acceleration = 6t - 18 = 0
t = 3s
at t = 3s, velocity = 3(3^2) -18*3 = -27m/s
displacement = 3^3 - 9*3^2 +4 = -50m
