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VLD [36.1K]
4 years ago
14

Please answer ASAP!! 3x+x-3/2=0

Mathematics
1 answer:
Aliun [14]4 years ago
7 0

Answer:

x=3/8

Step-by-step explanation:

3x+x-3/2=0

4x=3/2

8x=3

x=3/8

check:

3(3/8)+3/8-3/2=

9/8+(3-12)/8=

9/8-9/8=0

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What is the coordinate if (2,2) is reflected over the line x=2
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Answer:

-2,2

Step-by-step explanation:

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3 years ago
Choose the equation below that represents the line passing through the point (2, -4) with a slope of one half.
jekas [21]
<h3>Answer:</h3>

y = (1/2)x - 5

<h3>Step-by-step explanation:</h3>

Try the answers:

... -4 ≠ (1/2)·2 + 5

... -4 ≠ (1/2)·2 - 3

... -4 = (1/2)·2 - 5 . . . . . the third choice works

... -4 ≠ (1/2)·2 + 3

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You can write the point-slope form equation and simplify.

... y -k = m(x -h) . . . . . . equation for line of slope m through point (h, k)

... y -(-4) = (1/2)(x -2) . . . filled in with your values, m=1/2, (h, k) = (2, -4)

... y = (1/2)x -1 -4 . . . . subtract 4, eliminate parentheses

... y = (1/2)x - 5 . . . . . simplified. (Matches the 3rd selection.)

3 0
3 years ago
Read 2 more answers
Prove that<br>1/1+root 2 + 1/root2 + root3 + 1/root3 + root4 + 1/root8 +root9 = 2​
daser333 [38]

Step-by-step explanation:

LHS:

\frac{1}{1+\sqrt{2}}+\frac{1}{\sqrt{2}+\sqrt{3}}+\frac{1}{\sqrt{3}+\sqrt{4}}+\ldots \ldots \ldots \ldots \ldots+\frac{1}{\sqrt{8}+\sqrt{9}}1+21+2+31+3+41+……………+8+91

Rationalizing the denominator, we get

\Rightarrow\left(\frac{1}{1+\sqrt{2}} \times \frac{1-\sqrt{2}}{1-\sqrt{2}}\right)+\left(\frac{1}{\sqrt{2}+\sqrt{3}} \times \frac{\sqrt{2}-\sqrt{3}}{\sqrt{2}-\sqrt{3}}\right)+\left(\frac{1}{\sqrt{3}+\sqrt{4}} \times \frac{\sqrt{3}-\sqrt{4}}{\sqrt{3}-\sqrt{4}}\right)+\cdots \ldots+\left(\frac{1}{\sqrt{8}+\sqrt{9}} \times \frac{\sqrt{8}-\sqrt{9}}{\sqrt{8}-\sqrt{9}}\right)⇒(1+21×1−21−2)+(2+31×2−32−3)+(3+41×3−43−4)+⋯…+(8+91×8−98−9)

We know that,

\left(a^{2}-b^{2}\right)=(a+b)(a-b)(a2−b2)=(a+b)(a−b)

Now, on substituting the formula, we get,

=\frac{1-\sqrt{2}}{1-2}+\frac{\sqrt{2}-\sqrt{3}}{2-3}+\frac{\sqrt{3}-\sqrt{4}}{3-4}+\cdots \ldots \cdot \frac{(\sqrt{8}-\sqrt{9})}{8-9}=1−21−2+2−32−3+3−43−4+⋯…⋅8−9(8−9)

\Rightarrow \frac{1}{1+\sqrt{2}}+\frac{1}{\sqrt{2}+\sqrt{3}}+\frac{1}{\sqrt{3}+\sqrt{4}}+\cdots+\frac{1}{\sqrt{8}+\sqrt{9}}=(\sqrt{2}-1)+(\sqrt{3}-\sqrt{2})+(\sqrt{4}-\sqrt{3})+\cdots+(\sqrt{9}-\sqrt{8})⇒1+21+

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3 years ago
Find the constant variation for the direct variation given 
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6 0
3 years ago
I require someone to answer this question for me ASAP please?
elixir [45]

Answer:

x has to be less than 3

Step-by-step explanation:

3 0
3 years ago
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