All categories

3 years ago

Please answer ASAP!! 3x+x-3/2=0

Mathematics

1 answer:

Aliun [14]3 years ago

7 0

Answer:

x=3/8

Step-by-step explanation:

3x+x-3/2=0

4x=3/2

8x=3

x=3/8

check:

3(3/8)+3/8-3/2=

9/8+(3-12)/8=

9/8-9/8=0

You might be interested in

The ratio to isabella's money to shane's money is 3:11 if isabella has $33 how much money do shane and isabella have together us

alexgriva [62]

Shane and Isabella have 154 dollars

4 0

3 years ago

The Changs received a delivery of fuel oil totaling 35.00 gallons. The oil cost $3.05 per gallon. What did the Changs pay for th

Ede4ka [16]

Answer:

$106.75

Step-by-step explanation:

Since the cost of a gallon of oil cost $3.05, we are going to have the equation y = 3.05x, where x represents the number of gallons of oil.

Since the Changs have 35 gallons of oil, the equation would be;

3.05(35) = 106.75

The Changs paid $106.75 for the delivery.

7 0

2 years ago

Area of pallalelagram base 10cm , height 7cm

Neko [114]

A=base times height
A=10 times 7
A=70 cm²

5 0

3 years ago

I NEED HELP PLEASE I DONT UNDERSTAND AND CANT FAIL

butalik [34]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

What is the best approximation of the projection of (5,-1) onto (2,6)?

Hatshy [7]

Answer:

Hence, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\sqrt{10} }{5}$ , and the vector projection of $\vec a$ onto $\vec b$ = $\frac{1}{5} \hat i+\frac{3}{5} \hat j$ .

Step-by-step explanation:

We have given two points $(5, -1)$ and $(2, 6)$ .

Let, $\vec a=5\hat {i}-\hat {j}$ and $\vec b= 2\hat {i}+6\hat{j}$ .

and we have calculate the projection of $\vec a$ onto $\vec b$ .

Now,

For the calculation of projection, first we need to calculate the dot product of $\vec a$ and $\vec b$ .

$\vec a.\vec b=(5\hat {i}-\hat{j}).(2\hat{i}+6\hat{j})$

$=10-6$

$=4$

then, we have to calculate the magnitude of $\vec b$ .

$\mid {\vec {b}}\mid$ = $\sqrt{2^{2}+6^{2} }$ = $\sqrt{40}$ = $2\sqrt{10}$ .

Now, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\vec a.\vec b}{\mid b\mid}$

= $\frac{4}{2\sqrt{10} }$ $\frac{2}{\sqrt{10} } \times\frac{\sqrt{10} }{\sqrt{10} } =\frac{2\sqrt{10} }{10} = \frac{\sqrt{10} }{5}$

and the vector projection of $\vec a$ onto $\vec b$ = $\frac{\vec a. \vec b}{\mid\vec b \mid^{2} } . \vec b$

= $\frac{4}{40} . (2\hat i+ 6\hat j)$

= $\frac{1}{5} \hat i+\frac{3}{5} \hat j$

Hence, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\sqrt{10} }{5}$ , and the vector projection of $\vec a$ onto $\vec b$ = $\frac{1}{5} \hat i+\frac{3}{5} \hat j$ .

6 0

3 years ago