Question

X^2+y^2=169, 3x+2y=39 please answer using substitution and each step

Answer 1

Answer:

x=13,y=0

Step-by-step explanation:

We are given a system of equations

${x}^{2} + {y}^{2} = 169 - - eqn \: 1 \\ 3x + 2y = 39 - - eqn \: 2$

For equation 1,square all terms to reduce it

√x²+√y²=169

x+y=13

Make x the subject as required by the question to use substitution method

x=13-y

Plug x=13-y into eqn 2

3(13-y)+2y=39

39-3y+2y=39

39-y=39

y=39-39=0

Plug y=0 into equation 1

x+0=13

x=0