To solve for the time an object takes to hit the ground, the equation
<em>y</em> <em>= y₀ + v₀t + ½gt²</em>, or just <em>0 = y₀ +½gt²</em> since there is no initial velocity and the final y position is 0 (since it is on the ground). Therefore, <em>t = (−2y₀/g)^½.</em>
(-2*60/-9.8)^½ = 3.50 seconds.
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Answer:
where is the problem
Step-by-step explanation:
Answer: 0.10
Step-by-step explanation: The type 2 error is committed when the alternative hypothesis is rejected when it should have been accepted causing the researcher to accept the null hypothesis which is false.
Power is the probability of avoiding a type 2 error. That is ;
Power = 1 - P(type 2 error)
Given that power = 0.90 ; P(type 2 error) = probability of committing a type 2 error.
P(type 2 error)' = 1 - P(type 2 error) = Probability of not committing or avoiding a type 2 error
0.90 = 1 - P(type 2 error)
P(type 2 error) = 1 - 0.90
P(type 2 error) = 0.10
Answer:
1 pm
Step-by-step explanation:
We have to find their LCM, or least common multiple
Multiples of 36: 36, 72, 108, 144, 180, 216, ......
Multiples of 45: 45, 90, 135, 180, ....
180 mins is their LCM.
180 mins = 3 hours
10am + 3hours = 1 pm
-Chetan K
I’m not sure what that meant.