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Alenkinab [10]
3 years ago
11

Jane has 18 juice boxes, 24 bags of peanuts and 36 apples. She wants to make snack bags with same number of each thing in each b

ag. What is the greatest number of snack bags Jane can make?
Mathematics
1 answer:
pishuonlain [190]3 years ago
8 0

Answer:  6 snack bags.

Step-by-step explanation:

For this exercise it is important to remember the Greatest Common Divisor (GCD). This is defined as  the largest positive intener by which  you can divided evenly "n" numbers.

In  this case, you know that Jane has  18 juice boxes, 24 bags of peanuts and 36 apples. Therefore, the steps are the following:

1. You need to descompose 18, 24 and 36 into their prime factors, as below:

18=2*3*3=2*3^2\\\\24=2*2*2*3=2^3*3\\\\36=2*2*3*3=2^2*3^2

2. Now you must choose the common ones with the smallest exponent and multiply them.

Then, you get:

GCD=3*2\\\\GCD=6

Therefore, the greatest number of snack bags that Jane can make is:  6 snack bags.

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D(x)=(x^2-12x+20)/(3x)
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Vertical asymptote: x = 0

Horizontal asymptote: None

Slant asymptote: (1/3)x - 4

<u>Explanation:</u>

d(x) = \frac{x^{2}-12x+20}{3x}

      = \frac{(x-2)(x - 10)}{3x}

Discontinuities: (terms that cancel out from numerator and denominator):

Nothing cancels so there are NO discontinuities.

Vertical asymptote (denominator cannot equal zero):

3x ≠ 0  

<u>÷3</u>   <u>÷3 </u>

x ≠ 0

So asymptote is to be drawn at x = 0

Horizontal asymptote (evaluate degree of numerator and denominator):

degree of numerator (2) > degree of denominator (1)

so there is NO horizontal asymptote but slant (oblique) must be calculated.

Slant (Oblique) Asymptote (divide numerator by denominator):

  •        <u>(1/3)x - 4    </u>
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  •             <u>x²        </u>
  •                  -12x
  •                  <u>-12x         </u>
  •                             20 (stop! because there is no "x")

So, slant asymptote is to be drawn at (1/3)x - 4



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3 years ago
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