The answer is 5 i believe lol
Answer:
essentially, in these problems, youre finding the square root of each number. the square root should be a decimal thats in between two other numbers, and those will be the integers that the value of the square root is between. unless the value is exactly a number and a half, it will be closer to one integer than the other. the work is below.
square root of:
59= 7.68
68= 8.246
78= 8.83
93= 9.64
104= 10.198
124= 11.14
33= 5.74
185= 13.6
215= 14.66
these are just the square roots. but, as you can see, each number is between two other whole numbers on a number line. So, just write down what those numbers are.
7.68 is between 7 and 8
8.246 is between 8 and 9
8.83 is between 8 and 9
9.64 is between 9 and 10
10.198 is between 10 and 11
11.14 is between 11 and 12
5.74 is between 5 and 6
13.6 is between 13 and 14
14.66 is between 14 and 15
so, we know thw numbers that each decimal is between, but we have to find which one each is cloest to. in order to do that, just know that if the decimal is more than .5 its closer to the larger number, and its its less than .5, its closer to thw smaller number.
7.68 is closer to 8
8.246 is closer to 8
8.83 is closer to 9
9.64 is closer to 10
10.198 is closer to 10
11.14 is closer to 11
5.74 is closer to 6
13.6 is closer to 14
14.66 is closer to 15
Answer:
(a) The average cost function is 
(b) The marginal average cost function is 
(c) The average cost approaches to 95 if the production level is very high.
Step-by-step explanation:
(a) Suppose 
is a total cost function. Then the average cost function, denoted by 
, is
We know that the total cost for making x units of their Senior Executive model is given by the function
The average cost function is
(b) The derivative 
of the average cost function, called the marginal average cost function, measures the rate of change of the average cost function with respect to the number of units produced.
The marginal average cost function is
(c) The average cost approaches to 95 if the production level is very high.
![\lim_{x \to \infty} (\bar{C}(x))=\lim_{x \to \infty} (95+\frac{230000}{x})\\\\\lim _{x\to a}\left[f\left(x\right)\pm g\left(x\right)\right]=\lim _{x\to a}f\left(x\right)\pm \lim _{x\to a}g\left(x\right)\\\\=\lim _{x\to \infty \:}\left(95\right)+\lim _{x\to \infty \:}\left(\frac{230000}{x}\right)\\\\\lim _{x\to a}c=c\\\lim _{x\to \infty \:}\left(95\right)=95\\\\\mathrm{Apply\:Infinity\:Property:}\:\lim _{x\to \infty }\left(\frac{c}{x^a}\right)=0\\\lim_{x \to \infty} (\frac{230000}{x} )=0](https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Cto%20%5Cinfty%7D%20%28%5Cbar%7BC%7D%28x%29%29%3D%5Clim_%7Bx%20%5Cto%20%5Cinfty%7D%20%2895%2B%5Cfrac%7B230000%7D%7Bx%7D%29%5C%5C%5C%5C%5Clim%20_%7Bx%5Cto%20a%7D%5Cleft%5Bf%5Cleft%28x%5Cright%29%5Cpm%20g%5Cleft%28x%5Cright%29%5Cright%5D%3D%5Clim%20_%7Bx%5Cto%20a%7Df%5Cleft%28x%5Cright%29%5Cpm%20%5Clim%20_%7Bx%5Cto%20a%7Dg%5Cleft%28x%5Cright%29%5C%5C%5C%5C%3D%5Clim%20_%7Bx%5Cto%20%5Cinfty%20%5C%3A%7D%5Cleft%2895%5Cright%29%2B%5Clim%20_%7Bx%5Cto%20%5Cinfty%20%5C%3A%7D%5Cleft%28%5Cfrac%7B230000%7D%7Bx%7D%5Cright%29%5C%5C%5C%5C%5Clim%20_%7Bx%5Cto%20a%7Dc%3Dc%5C%5C%5Clim%20_%7Bx%5Cto%20%5Cinfty%20%5C%3A%7D%5Cleft%2895%5Cright%29%3D95%5C%5C%5C%5C%5Cmathrm%7BApply%5C%3AInfinity%5C%3AProperty%3A%7D%5C%3A%5Clim%20_%7Bx%5Cto%20%5Cinfty%20%7D%5Cleft%28%5Cfrac%7Bc%7D%7Bx%5Ea%7D%5Cright%29%3D0%5C%5C%5Clim_%7Bx%20%5Cto%20%5Cinfty%7D%20%28%5Cfrac%7B230000%7D%7Bx%7D%20%29%3D0)
I can't see the whole problem
