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Serjik [45]
3 years ago
5

If x< 0 and y<0 where is the point (x,y) located

Mathematics
1 answer:
Phoenix [80]3 years ago
8 0

Answer: 0

Step-by-step explanation:

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4 years ago
Find the maximum/minimum value of the function y = x2 - (5/3)x + 31/36.
AysviL [449]

Answer:

A

Step-by-step explanation:

Given a parabola in standard form, y = ax² + bx + c ( a ≠ 0 ), then

minimum/ maximum value is the y- coordinate of the vertex.

The x- coordinate of the vertex is

x_{vertex} = - \frac{b}{2a}

y = x² - \frac{5}{3} x + \frac{31}{36} ← is in standard form

with a = 1 and b = - \frac{5}{3} , thus

\frac{x}{vertex} = - \frac{-\frac{5}{3} }{2} = \frac{5}{6}

Substitute this value into y

y = (\frac{5}{6} )² - \frac{5}{3} (\frac{5}{6} ) + \frac{31}{36}

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minimum value = \frac{1}{6} → A

3 0
3 years ago
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