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mestny [16]
3 years ago
9

H function is even, odd, or neither. b. g(x) = x² - 2 Is it odd or even

Mathematics
1 answer:
o-na [289]3 years ago
4 0

g(x) = x^2 - 2 \text{ is even function }

<em><u>Solution:</u></em>

Given that,

g(x) = x^2 - 2

We have to find whether the above function is odd or even

If a function is: y = f(x)

If f(-x) = f(x), the function is even

If f(-x) = - f(x), the function is odd

Which is,

\mathrm{Even\:Function:\:\:A\:function\:is\:even\:if\:}f\left(-x\right)=f\left(x\right)\mathrm{\:for\:all\:}x\in \mathbb{R}\\\\\mathrm{Odd\:Function:\:\:A\:function\:is\:odd\:if\:}f\left(-x\right)=-f\left(x\right)\mathrm{\:for\:all\:}x\in \mathbb{R}

From given,

g(x) = x^2 - 2

Replace x with -x

g(-x) = (-x)^2 - 2\\\\g(-x) = x^2 - 2

Therefore,

g(x) = g(-x)

Thus the function g(x) is even

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