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Talja [164]
3 years ago
9

1. Look at the lines in the grid below.

Mathematics
1 answer:
GenaCL600 [577]3 years ago
6 0
The answer is C. Hope this helps
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Bobby has just turned 56 years old
Pani-rosa [81]
Um how am i supposed to answer
6 0
3 years ago
I NEED HELP QUICKLY!!! What is the sum of the first 140 positive multiples of 3?
garri49 [273]

Answer:

C

Step-by-step explanation:

The multiples of 3 are

3, 6, 9, 12, 15, ...........

The terms form an arithmetic sequence with common difference of 3.

The sum to n terms is

S_{n} = \frac{n}{2} [2a₁ + (n - 1)d ]

where a₁ is the first term and d the common difference

Here a₁ = 3 and d = 3, thus

S_{140} = \frac{140}{2} [ (2 × 3) + (139 × 3) ]

                            = 70(6 + 417) ] = 70 × 423 = 29610 → C

5 0
3 years ago
Which ordered pairs lie on the graph of the exponential function f(x) = 3 (1/4)x
sineoko [7]
The first two pairs.. just substitute the x-coordinate and find y
8 0
3 years ago
Round to the nearest ten and hundred 829
Musya8 [376]
To the nearest ten, 829 would become <em><u>830</u></em> because the ones digit (9) is closer to 30 than it is to 20. So we would round up.

To round to the nearest hundred, we look at the tens and ones digit. 29 is less than 50 so we would have to round down to <em><u>800</u></em> instead of rounding up to 900.

Hope that helps :)
4 0
4 years ago
Read 2 more answers
Solve the equation for x in terms of c
Dovator [93]

solve\:for\:x,\:\frac{2}{3}\left(cx+\frac{1}{2}\right)-\frac{1}{4}=\frac{5}{2}

\mathrm{Add\:}\frac{1}{4}\mathrm{\:to\:both\:sides}

\frac{2}{3}\left(cx+\frac{1}{2}\right)-\frac{1}{4}+\frac{1}{4}=\frac{5}{2}+\frac{1}{4}

\frac{2}{3}\left(cx+\frac{1}{2}\right)=\frac{11}{4}

\mathrm{Multiply\:both\:sides\:by\:}3

3\cdot \frac{2}{3}\left(cx+\frac{1}{2}\right)=\frac{11\cdot \:3}{4}

2cx+1=\frac{33}{4}

\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}

2cx+1-1=\frac{33}{4}-1

2cx=\frac{29}{4}

\mathrm{Divide\:both\:sides\:by\:}2c

x=\frac{29}{8c}

<h3>Therefore, correct option is C. option.</h3><h3>C. x=29/8c</h3>
8 0
3 years ago
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