Answer:
The correct option is second one i.e 24 units.
Therefore the height of the triangle is
![NR=24\ units](https://tex.z-dn.net/?f=NR%3D24%5C%20units)
Step-by-step explanation:
Given:
An equilateral triangle has all sides equal.
ΔMNO is an Equilateral Triangle with sides measuring,
![NM = MO = ON =16\sqrt{3}](https://tex.z-dn.net/?f=NM%20%3D%20MO%20%3D%20ON%20%3D16%5Csqrt%7B3%7D)
NR is perpendicular bisector to MO such that
.NR ⊥ Bisector.
To Find:
Height of the triangle = NR = ?
Solution :
Now we have a right angled triangle NRM at ∠R =90°,
So by applying Pythagoras theorem we get
![(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}](https://tex.z-dn.net/?f=%28%5Ctextrm%7BHypotenuse%7D%29%5E%7B2%7D%20%3D%20%28%5Ctextrm%7BShorter%20leg%7D%29%5E%7B2%7D%2B%28%5Ctextrm%7BLonger%20leg%7D%29%5E%7B2%7D)
Substituting the values we get
![(MN)^{2} = (MR)^{2}+(NR)^{2}\\\\(16\sqrt{3})^{2}=(8\sqrt{3})^{2}+(NR)^{2}\\\\(NR)^{2}=768-192=576\\Square\ rooting\ we\ get\\NR=\sqrt{576}=24\ units](https://tex.z-dn.net/?f=%28MN%29%5E%7B2%7D%20%3D%20%28MR%29%5E%7B2%7D%2B%28NR%29%5E%7B2%7D%5C%5C%5C%5C%2816%5Csqrt%7B3%7D%29%5E%7B2%7D%3D%288%5Csqrt%7B3%7D%29%5E%7B2%7D%2B%28NR%29%5E%7B2%7D%5C%5C%5C%5C%28NR%29%5E%7B2%7D%3D768-192%3D576%5C%5CSquare%5C%20rooting%5C%20we%5C%20get%5C%5CNR%3D%5Csqrt%7B576%7D%3D24%5C%20units)
Therefore the height of the triangle is
![NR=24\ units](https://tex.z-dn.net/?f=NR%3D24%5C%20units)
I wish i could help but i dont know the answer
Answer:
Option C. ![26\ units](https://tex.z-dn.net/?f=26%5C%20units)
Step-by-step explanation:
we know that
Triangles ADE and ABC are similar by AA similarity postulate
AB=2AD
Apply proportion
![\frac{AD}{AB}=\frac{8x-6}{12x+4}\\ \\\frac{AD}{2AD}=\frac{8x-6}{12x+4}\\ \\\frac{1}{2}=\frac{8x-6}{12x+4}\\ \\12x+4=16x-12\\ \\16x-12x=4+12\\ \\4x=16\\ \\x=4\ units](https://tex.z-dn.net/?f=%5Cfrac%7BAD%7D%7BAB%7D%3D%5Cfrac%7B8x-6%7D%7B12x%2B4%7D%5C%5C%20%5C%5C%5Cfrac%7BAD%7D%7B2AD%7D%3D%5Cfrac%7B8x-6%7D%7B12x%2B4%7D%5C%5C%20%5C%5C%5Cfrac%7B1%7D%7B2%7D%3D%5Cfrac%7B8x-6%7D%7B12x%2B4%7D%5C%5C%20%5C%5C12x%2B4%3D16x-12%5C%5C%20%5C%5C16x-12x%3D4%2B12%5C%5C%20%5C%5C4x%3D16%5C%5C%20%5C%5Cx%3D4%5C%20units)
Find the length of segment DE
![DE=8x-6=8(4)-6=26\ units](https://tex.z-dn.net/?f=DE%3D8x-6%3D8%284%29-6%3D26%5C%20units)
(12/-3)+(-14*4)
(-4)+(-56)
[-60]
-- i dont understand what you mean by "opposite of" so i assumed you meant negative??
Answer:
xfbxcnfcvfxfhdfxbdfhsdxcbndf
Step-by-step explanation: