Using the binomial distribution, the probabilities are given as follows:
- 0.3675 = 36.75% probability that more than 4 weigh more than 20 pounds.
- 0.1673 = 16.73% probability that fewer than 3 weigh more than 20 pounds.
- Since P(X > 7) < 0.05, it would be unusual if more than 7 of them weigh more than 20 pounds.
<h3>What is the binomial distribution formula?</h3>
The formula is:


The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
The values of the parameters for this problem are:
n = 10, p = 0.4.
The probability that more than 4 weigh more than 20 pounds is:

In which:

Then:






Hence:


0.3675 = 36.75% probability that more than 4 weigh more than 20 pounds.
The probability that fewer than 3 weigh more than 20 pounds is:
P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0061 + 0.0403 + 0.1209 = 0.1673
0.1673 = 16.73% probability that fewer than 3 weigh more than 20 pounds.
For more than 7, the probability is:





Since P(X > 7) < 0.05, it would be unusual if more than 7 of them weigh more than 20 pounds.
More can be learned about the binomial distribution at brainly.com/question/24863377
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Answer:
1/2
Step-by-step explanation:
1) the sample space is 1 through 6
2) numbers less than 4 on the number cube 1, 2, and 3 3#s
total amount of #s is 6
probability = numbers less than 4/total amount of #s:
3/6
1/2
Answer:
x=4 y=8
Step-by-step explanation:
Solve for the first variable in one of the equations, then substitute the result into the other equation
Please go into more detail about the question then u will be able to help you
Answer:
Around 34.14% of the cookies are between 11.32 and 11.35 grams.
Step-by-step explanation:
In a normal distribution around 68.28% of the values are around minus one to one standard deviation. In this case we want to know the percentage of values that are between zero and one standard deviation, therefore the percentage of values that are in that range is given by 68.28% / 2 , which is equal to 34.14%.