Answer:
Angle-Angle-Side (AAS)
Step-by-step explanation:
Given triangles; ΔABD and ΔCBD
<A = <C = (right angle property)
AB ║ DC (given)
Then,
DA ║ CB
<B ≅ <D (congruent property)
DB ≅ BD (similarity property)
<D + <B = <B + <D (complementary angles, and property of triangles)
Therefore by Angle-Angle-Side (AAS),
∆ABD ≅ ∆CBD
GIVEN:
We are given the following polynomial;
Required;
We are required to factorize this polynomial completely.
Step-by-step explanation;
To factorize this polynomial, we start by grouping;
We now take the common factor in each group;
Next, we factorize the first parenthesis. To do this we set the equation equal to zero and solve for x as follows;
Therefore, the factors of the other parenthesis are;
Therefore, the complete factorization of the polynomial is;
ANSWER:
Option C is the correct answer.