Question

Jeremy rode his bicycle in a race. He averaged 15 mph and began the race 1 hour ahead of the other riders. The variable d represents Jeremy's distance ridden, in miles. The variable t represents the number of hours since the other riders began to race. Which equation can be used to determine the distance Jeremy rode t hours into the race?
d = 15t + 1

d=15(t+1)

d=15(t−1)

d=15t−1

Answer 1

Answer:

$d=15(t+1)$

Step-by-step explanation:

The $15$ represents Jeremy's speed, which is 15 miles per hour.

The $(t+1)$ represents the total number of hours Jeremy rode his bike, including the 1 hour head start he got.  This adds his head start ($1$) and the rest of the time he has ridden ($t$).

As mentioned in the problem, $d$ represents the total distance in miles that Jeremy rode on his bike.

Answer 2

D = 15(t + 1)

Explanation:
It would be t + 1 rather than t - 1 because he has one *more* hour compared to the other riders.
The reason why t + 1 is in parentheses is because when solving, you'd have to first add instead of multiply.