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Art [367]
3 years ago
14

By what factor does the rate change in each of the following cases (assuming constant temperature)?

Chemistry
1 answer:
Zanzabum3 years ago
3 0

Answer:

a) The rate of reaction increases by factor of 2.

b) The rate of reaction increases by factor of 0.25.

c) The rate of reaction increases by factor of 9.

Explanation:

a)

Rate of the reaction ;

R=k[A]^1

if [A] is doubled, then rate of the reaction = R'

R'=k[2A]^1

R'=2k[A]

R'=2R

The rate of reaction increases by factor of 2.

b)

Rate of the reaction ;

R=k[B]^2

if [B] is halved, then rate of the reaction = R'

R'=k[\frac{B}{2}]^2

R'=\frac{1}{4}k[B]^2

R'=0.25R

The rate of reaction increases by factor of 0.25.

c)

Rate of the reaction ;

R=k[C]^2

if [C] is tripled, then rate of the reaction = R'

R'=k[3C]^2

R'=9k[C]^2

R'=9R

The rate of reaction increases by factor of 9.

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2S+3O2 -> 2SO3 Indicate whether S or O2 is the limiting reactant, 3mol S 4mol O, 3mol S 5mol O, 3mol S 3mol? Elemental S reac
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Balanced chemical reaction: 2S + 3O₂ → 2SO₃.

1) Answer is: oxygen is limiting reactant.

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From balanced chemical reaction: n(S) : n(O₂) = 2 : 3.

3 mol : n(O₂) = 2 : 3.

n(O₂) = (3 · 3 mol) ÷ 2.

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2) Answer is: sulfur(S) is limiting reactant.

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From balanced chemical reaction: n(S) : n(O₂) = 2 : 3.

n(S) : 5 mol = 2 : 3.

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3) Answer is: oxygen (O₂) is limiting reactant.

n(S) = 3 mol.

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