1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Karo-lina-s [1.5K]
3 years ago
10

Which of the following statements is/are CORRECT?1. For a chemical system, if the reaction quotient (Q) is greater than K, react

ant must be converted to products to reach equilibrium.2. For a chemical system at equilibrium, the forward and reverse rates of reaction are equal.3. For a chemical system at equilibrium, the concentrations of products divided by the concentrations of reactants equals one.1 only2 only3 only1 and 21, 2, and 3
Chemistry
1 answer:
tankabanditka [31]3 years ago
8 0

Explanation:

A chemical equilibrium is defined as the state of reaction in which the rate of forward reaction is equal to the rate of backward reaction.

When Q > K_{eq}, then it means that the reaction is proceeding in the backward reaction. Whereas if Q < K_{eq}, then it means that the reaction is proceeding in the forward direction. Hence, formation of products will be favored.

On the other hand, if Q = K_{eq}, then it means reaction is at equilibrium.

At equilibrium, it is not necessary that the concentrations of products divided by the concentrations of reactants equals one.

Thus, we can conclude that the statement for a chemical system at equilibrium, the forward and reverse rates of reaction are equal, is correct.

You might be interested in
Calculate the concentration of acetic acid and acetate ion in a 0.2 M acetate buffer at pH 5. The p K a of acetic acid is 4.76
Levart [38]

Answer:

[Acetic acid] = 0.07 M

[Acetate] = 0.13 M

Explanation:

pH of buffer = 5

pKa of acetic acid = 4.76

pH=p_{Ka} + log\frac{[Salt]}{[Acid]}

Now using Henderson-Hasselbalch equation

5=4.76 + log\frac{[Acetate]}{[Acetic\;acid]}

log\frac{[Acetate]}{[Acetic\;acid]} = 0.24

\frac{[Acetate]}{[Acetic\;acid]} = 1.74  ....... (1)

It is given that,

[Acetate] + [Acetic acid] = 0.2 M     ....... (2)

Now solving both the above equations

[Acetate] = 1.74[Acetic acid]

Substitute the concentration of acetate ion in equation (2)

1.74[Acetic acid] + [Acetic acid] = 0.2 M

[Acetic acid] = 0.2/2.74 = 0.07 M

[Acetate] = 0.2 - 0.07 = 0.13 M

5 0
3 years ago
Write the half-reactions as they occur at each electrode and the net cell reaction for this electrochemical cell containing indi
AlexFokin [52]

Explanation:

The given cell reaction is as follows.

       In(s)| In^{3+}(aq) || Cd^{2+}(aq) | Cd(s)

Hence, reactions taking place at the cathode and anode are as follows.

At anode ; Oxidation-half reaction : In(s) \rightarrow In^{3+}(aq) + 3e^{-} ...... (1)

At cathode; Reduction-half reaction : Cd^{2+}(aq) + 2e^{-} \rightarrow Cd(s) ....... (2)

Hence, balance the half reactions by multiplying equation (1) by 2 and equation (2) by 3.

Therefore, net cell reaction is as follows.

      2In(s) \rightarrow 2In^{3+}(aq) + 6e^{-}

      3Cd^{2+}(aq) + 6e^{-} \rightarrow 3Cd(s)

Net reaction: 2In(s) + 3Cd^{2+}(aq) \rightarrow 2In^{3+}(aq) + 3Cd(s)

Thus, we can conclude that the overall cell reaction is as follows.

        2In(s) + 3Cd^{2+}(aq) \rightarrow 2In^{3+}(aq) + 3Cd(s)

4 0
3 years ago
Which of the following bodily organs or systems can be affected by ionizing radiation?
GrogVix [38]
The correct answer is the fourth option. The nervous system is the system in the body which can be affected by ionizing radiation. Exposure to this kind of radiation may lead to changes in motor function or neurological disorders.
5 0
3 years ago
HURRY PLS! A chemical reaction takes place in which energy is released. Arrange the reaction’s characteristics in order from sta
belka [17]

Answer:

The difference between the energy of the reactants and the energy of the products is called the enthalpy change (∆H) of the reaction. For an exothermic reaction, the enthalpy change is always negative. In an endothermic reaction, the products are at a higher energy than the reactants.

Explanation:

7 0
3 years ago
Read 2 more answers
A balloon contains 2.0 L of air at 101.5 kPa . You squeeze the balloon to a volume of 0.25 L.
8_murik_8 [283]
<h3>Answer:</h3>

812 kPa

<h3>Explanation:</h3>
  • According to Boyle's law pressure and volume of a fixed mass are inversely proportional at constant absolute temperature.
  • Mathematically, P\alpha \frac{1}{V}

At varying pressure and volume;

P1V1=P2V2

In this case;

Initial volume, V1 = 2.0 L

Initial pressure, P1 = 101.5 kPa

Final volume, V1 = 0.25 L

We are required to determine the new pressure;

P2=\frac{P1V1}{V2}

Replacing the known variables with the values;

P2=\frac{(101.5)(2.0L)}{0.25L}

           = 812 kPa

Thus, the pressure of air inside the balloon after squeezing is 812 kPa

8 0
3 years ago
Other questions:
  • One of the human body's adaptation is to sweat when it gets too hot. Sweat glands in the glands in the skin produce a solution o
    15·1 answer
  • Which group on the periodic table contains only metals? the second group
    13·2 answers
  • The standard entropy of Pb(s) at 298.15 K is 64.80 J K–1 mol–1. Assume that the heat capacity of Pb(s) is given by: CP,m(Pb, s)
    7·1 answer
  • What is the oxidation number for Cl? -2 +2 -1 +1
    15·2 answers
  • Which of the following chemical equations corresponds to the standard molar enthalpy of formation of Na_2CO_3(s)?
    14·1 answer
  • Question 1 (True/False Worth 4 points) (03.06 LC) An instantaneous dipole occurs when a molecule's moving electrons are briefly
    10·2 answers
  • Is comets greater than asteroids
    11·2 answers
  • Given the balanced equation: Pb(NO₃)₂(aq) + 2NaCl(aq) ➔ PbCl₂(s) + 2NaNO₃(aq). What type of reaction is represented by this equa
    15·1 answer
  • (SCIENCE)
    12·1 answer
  • The _____ ______ ______ is the average of ______ _____ of a particular atom.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!