The graph below shows a reaction to which a catalyst has been added. How would the graph be different if it showed the same reac
tion without a catalyst?
A. The width of region 2 would be smaller.
B. The difference in the heights of regions 1 and 3 would be larger.
C. The height of region 2 would be larger
D. The distance between regions 1 and 3 would be smaller
A. The width of region 2 would be smaller.
B. The difference in the heights of regions 1 and 3 would be larger.
C. The height of region 2 would be larger
D. The distance between regions 1 and 3 would be smaller
1 answer:
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- 0.05 L needs to be added to the original 0.12 L solution in order to dilute it from 0.13 M to 0.23 M.
The dilution problem uses the equation :
The initial molarity (concentration) 0.13 M
The initial volume = 0.12 L
The desired molarity (concentration) = 0.23 M
The volume of the desired solution = ( 0.12 + x L )
Substituting values in above equation;
(0.13 M ) (0.12 L) = (0.23 M ) (0.12 L + x L)
0.0156 M L = 0.0276 M L + 0.23 x M L
- 0.012 M L = 0.23 x M L
x = - 0.05
Therefore, - 0.05 L needs to be added to the original 0.12 L solution in order to dilute it from 0.13 M to 0.23 M.
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