First, subtract 700 from both sides and you are left with .15m≤50
Then divide both sides by .15 and you are left with m ≤ 333.33. Thus, the limo can only travel 333.33 miles.
It would be a straight horizontal line on y axis 19
F(x) = 5x - 2
f(-3/5) = 5(-3/5) - 2
f(-3/5) = -15/5 - 2
f(-3/5) = -3 - 2
f(-3/5) = -5
Answer:
Step-by-step explanation:
Find the sum of the first 42 terms of the following series, to the nearest integer.
2,7,12
Solution
The sum is given by
SUM_n=n/2*(a_1+a_n)
a_n=a_1+(n-1)d
a_1=2, n=42, d=5
The 42nd term is therefore given by
a_42=2+(42-1)5=207
SUM_42=42/2*(2+207)=21*209=4389
The sum of the first 42 terms of the series, therefore, is 4389
Using the distance formula
d= square root of (x2-x1)^2+(y2-y1)^2
(9-9)^2+(10-3)^2
0^2+7^2
0+49
Square root of 49 is 7
d=7
