I think the answer is he should've added t instead of subtracting t.
-1/4
- for a negative slope
rise over run
rises 1
runs 4
Two lines that are parallel have the same slope. Thus, the slope of the given line is 2 and the slope of the new line is also 2.
General slope-intercept equation of a str. line is y = mx + b.
Let m = 2: y = 2x + b
This new line passes thru (3,11). Thus, subst. 3 for x and 11 for y in
y = 2x + b, to find b:
11 = 2(3)+b
11 = 6 + b so b=5
Thus, the equation of the new line, parallel to the old, is y = 2x + 5.
Answer: 3g + 4y - 13 + 2t
Step-by-step explanation:
It's C)
the graph is decrasing, so the variable rate is negative (-2/3)
the rest was quite easy, you just take a look at where the graph cuts the y-axis and determine the rest from the rate of going up or down (increase/decrease)
