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Damm [24]
3 years ago
11

Which graph represents the function f(x) = (x – 3)2?

Mathematics
2 answers:
Monica [59]3 years ago
7 0

Answer:

Graph 2

Step-by-step explanation:

Snowcat [4.5K]3 years ago
6 0

Answer:

Graph 3 on Edg.

Step-by-step explanation:

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The ratio of volume of a cone and a hemisphere of same base radius and height is?
aliya0001 [1]

Answer:

1/2

Step-by-step explanation:

Since it is given that the cone and the hemisphere have the same height, and since the height of a hemisphere would be equal to its radius, the cones height must also be equal to its base radius.

With this information we can use the respective volume formulas.

Hemisphere:  \frac{2}{3}πr^3

Cone:  \frac{1}{3}πhr^2

Since h (height) = r we can say the cone volume equals:

\frac{1}{3}πr^3

Now to find the ratio we divide the cone volume equation by the hemisphere volume equation

pi and r^3 cancels out from the division and we are left with

ratio = (1/3)/(2/3)

ratio = 1/2

7 0
3 years ago
The sum of 3 consecutive even numbers of 78
Jet001 [13]
26, 24, 28 could be the answer
3 0
3 years ago
Read 2 more answers
8÷2(2+2)<br>what is the anwer<br>​
Colt1911 [192]

Answer:

1

Step-by-step explanation:

8/2(4)

8/8

1

4 0
2 years ago
Use the binomial theorem to show that 7^n + 2 is divisible by 3, where n is a positive integer.
masha68 [24]

By the binomial theorem,

7^n=(6+1)^n=6^n+n6^{n-1}+\dbinom n26^{n-2}+\cdots+\dbinom n{n-2}6^2+n6^1+1

Each term containing a factor 6 is divisible by 3, since 3 divides 6. The remaining 1 and 2 sum to 3, which is also divisible by 3.

7 0
3 years ago
Apply Crammer's Rule to find the solution to the following quations .2x + 3y = 1, 3x + y = 5​
Bond [772]

Answer:

The solution to the equation system given is:

  • <u>x = 2</u>
  • <u>y = -1</u>

Step-by-step explanation:

First, we must know the equations given:

  1. 2x + 3y = 1
  2. 3x + y = 5​

Following Crammer's Rule, we have the matrix form:

\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] =\left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}1\\5\end{array}\right]

Now we solve using the determinants:

x=\frac{\left[\begin{array}{ccc}1&3\\5&1\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(1*1)-(5*3)}{(2*1)-(3*3)} = \frac{1-15}{2-9} =\frac{-14}{-7} = 2

y=\frac{\left[\begin{array}{ccc}2&1\\3&5\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(2*5)-(3*1)}{(2*1)-(3*3)}=\frac{10-3}{2-9} =\frac{7}{-7}=-1

Now, we can find the answer which is x= 2 and y= -1, we can replace these values in the equation to confirm the results are right, with the first equation:

  • 2x + 3y = 1
  • 2(2) + 3(-1)= 1
  • 4 - 3 = 1
  • 1 = 1

And, with the second equation:

  • 3x + y = 5​
  • 3(2) + (-1) = 5
  • 6 - 1 = 5
  • 5 = 5

 

4 0
2 years ago
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