1) a
2) c
#1 explanation:
x^4-20x^2=-64
x^4-20x^2+64=0
(find a number that multiplies to the last number aka 64 and adds up to b aka 20)
((x-4)(x-16))^2
x= -2,2,-4,4
same for #2 w different variable and numbers
Sent a picture of the solution to the problem (s).
Answer: Rico is right.
(-1)(3x + 5)²
Step-by-step explanation: If it were the difference of two squares, the -30x would not be there.
It makes sense to factor out (-1) fry the trinomial, leaving all positive terms.
Then factor 9x² + 30x + 25 as
(3x + 5)²
