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3 years ago

Help asap 40 ptss (:

Mathematics

2 answers:

bearhunter [10]3 years ago

5 0

It's obviously not A or D since the width is supposed to be 6yd longer.
It can't be C, because 16 x 22 is not 160.
Therefore, the answer is B.

tia_tia [17]3 years ago

3 0

W(w + 6) = 160
w^2 + 6w - 160 = 0
w = 10 , -16 ( ignore the negative)

Answer:- width = 10 and length = 16

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Help me with this for 50 points.

inn [45]

Answer:

1/2 or 1:2

Step-by-step explanation:

3 circles to 6 squares

3/6 simplified is 1/2

6 0

2 years ago

Long Division: (3x^4-8x^3-x^2+9x+5) / (x-2) pleaseee answer this

Drupady [299]

3x⁴ = 3x³ • x, and

3x³ (x - 2) = 3x⁴ - 6x³

Subtract this from the numerator to get a remainder of

(3x⁴ - 8x³ - x² + 9x + 5) - (3x⁴ - 6x³) = -2x³ - x² + 9x + 5

-2x³ = -2x² • x, and

-2x² (x - 2) = -2x³ + 4x²

Subtract this from the previous remainder to get a new remainder of

(-2x³ - x² + 9x + 5) - (-2x³ + 4x²) = -5x² + 9x + 5

-5x² = -5x • x, and

-5x (x - 2) = -5x² + 10x

Subtract this from the last remainder to get a new one of

(-5x² + 9x + 5) - (-5x² + 10x) = -x + 5

-x = -1 • x, and

-1 (x - 2) = -x + 2

This gives a new remainder of

(-x + 5) - (-x + 2) = 3

3 does not divide x, so we're done.

So, we have

(3x⁴ - 8x³ - x² + 9x + 5) / (x - 2) = 3x³ - 2x² - 5x - 1 + 3/(x - 2)

7 0

3 years ago

What is the sum of the first five terms of a geometric series with a1 = 6 and r = 1/3? Express your answer as an improper fracti

Likurg_2 [28]

Answer:

242/27

Step-by-step explanation:

Using the formula for the sum, you can fill in the given values and do the arithmetic.

Sn = a1·(r^n -1)/(r -1)

S5 = 6·((1/3)^5 -1)/(1/3 -1) = 6(-242/243)/(-2/3) = 6·(121/81)

S5 = 242/27

_____

Or, you can write the terms and add them up. The sum is ...

6 + 2 + 2/3 + 2/9 + 2/27 = (162 +54 +18 +6 +2)/27 = 242/27

5 0

3 years ago

Given sinθ=- 3/5 and cscθ=-5/3 in quadrant III, find the value of other trigonometric functions using a Pythagorean Identity. Sh

Yakvenalex [24]

Let ABC be a triangle in the 3rd quadrant, right-angled at B.
So, AB-> Perpendicular BC -> Base AC -> Hypotenuse.
Given: sinÎ¸=-3/5 cosecÎ¸=-5/3
According to Pythagorean theorem, square of the hypotenuse is equal to the sum of square of the other two sides.
Therefore in triangle ABC, ă€–ACă€—^2=ă€–ABă€—^2+ă€–BCă€—^2 ------
--(1)
Since sinÎ¸=Perpendicular/Hypotenuse ,
AC=5 and AB=3
Substituting these values in equation (1)

ă€–BCă€—^2=ă€–ACă€—^2-ă€–ABă€—^2

ă€–BCă€—^2=5^2-3^2

ă€–BCă€—^2=25-9

ă€–BCă€—^2=16

BC=4 units

Since the triangle is in the 3rd quadrant, all trigonometric ratios, except tan
and cot are negative.
So,cosÎ¸=Base/Hypotenuse CosÎ¸=-4/5
secÎ¸=Hypotnuse/Base secÎ¸=-5/4
tanÎ¸=Perpendicular/Base tanÎ¸=3/4
cotÎ¸=Base/Perpendicular cotÎ¸=4/3

4 0

3 years ago

How to write 4.651 in expanded form with decimals?

dsp73

Answer:

$0.4651 \times {10}^{1}$

5 0

2 years ago