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Delicious77 [7]
3 years ago
15

Help asap 40 ptss (:

Mathematics
2 answers:
bearhunter [10]3 years ago
5 0
It's obviously not A or D since the width is supposed to be 6yd longer. 
It can't be C, because 16 x 22 is not 160.
Therefore, the answer is B.
tia_tia [17]3 years ago
3 0
W(w + 6) = 160
w^2 + 6w - 160 = 0
w = 10 , -16 ( ignore the negative)

Answer:-   width = 10 and length = 16
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THIS IS MY LAST QUETSION!!!! Please help!!!
DedPeter [7]

Answer:

x=19(rounded) or 18.7882942281

Step-by-step explanation:

a^2+b^2=C^2

8^2+17^2=C^2

64+289= C^2

353=C^2

\sqrt{353} =\sqrt{C^2}\\

18.7882942281= C

19= C

7 0
3 years ago
I need help on number two
SVEN [57.7K]

Answer:

2 y = 100

10 y = 20

20 y = 10

Step-by-step explanation:

To find the answer divide Y by X since y is 200 in the first and x is 1 divide 200 by the second one and you will find you answer.

8 0
3 years ago
Calculate the volume of each diagrams.
wariber [46]

The volume of the solid objects are 612π in³ and 1566πcm³

<h3>Volume of solid object</h3>

The given objects are composite figures consisting of two shapes.

The volume of the blue figure is expressed as;

Volume = Volume of cylinder + volume of hemisphere

Volume = πr²h + 2/3πr³

Volume =  πr²(h + 2/3r)

Volume =  π(6)²(13+2/3(6))

Volume = 36π(13 + 4)

Volume = 612π in³

For the other object

Volume = Volume of cylinder + volume of cone

Volume = πr²h + 1/3πr²h

Volume =  π(9)²(15) + 1/3π(9)²(13)

Volume=  81π (15+13/3)
Volume= 1566πcm³

Hence the volume of the solid objects are 612π in³ and 1566πcm³

Learn more on volume of composite figures here: brainly.com/question/1205683

#SPJ1

8 0
2 years ago
Hey how do you get from standard form to vertex form?
vlabodo [156]

Explanation:

Conversion of a quadratic equation from standard form to vertex form is done by completing the square method.

Assume the quadratic equation to be \mathbf{ax^{2}+bx+c=0} where x is the variable.

Completing the square method is as follows:

  1. send the constant term to other side of equal                 \mathbf{ax^{2}+bx=-c}
  2. divide the whole equation be coefficient of \mathbf{x^{2}}, this will give     \mathbf{x^{2}+\frac{b}{a}x=- \frac{c}{a}}
  3. add \mathbf{(\frac{b}{2a})^{2}} to both side of equality                                   \mathbf{x^{2}+2\times\frac{b}{2a}x+\frac{b}{2a}^{2}=-\frac{c}{a}+\frac{b}{2a}^{2}}
  4. Make one fraction on the right side and compress the expression on the left side                                                                          \mathbf{(x+\frac{b}{2a})^{2}=\frac{b^{2}-4ac}{4a^{2}}}
  5. rearrange the terms will give the vertex form of standard quadratic equation                                                                 \mathbf{a(x+\frac{b}{2a})^{2}-\frac{b^{2}-4ac}{4a}=0}

Follow the above procedure will give the vertex form.

(NOTE : you must know that \mathbf{(x+a)^{2}=x^{2}+2ax+a^{2}}. Use this equation in transforming the equation from step 3 to step 4)

8 0
3 years ago
I will mark you brainliest!
kari74 [83]

Answer:

F(x) < 0 over the intervals (-∞, -0.7) and (0.76, 2.5).

Step-by-step explanation:

The line is below the x-axis at those intervals

7 0
3 years ago
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