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3 years ago

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A tank whose bottom is a mirror is filled with water to a depth of 20.6 cm . A small fish floats motionless 7.80 cm under the su

rface of the water. Part A
What is the apparent depth of the fish when viewed at normal incidence to the water?
Express your answer in centimeters. Use 1.33 for the index of refraction of water.
Part B
What is the apparent depth of the reflection of the fish in the bottom of the tank when viewed at normal incidence?
Express your answer in centimeters. Use 1.33 for the index of refraction of water.

1 answer:

Finger [1]3 years ago

4 0

Answer:

Explanation:

A ) Index of refraction = real depth / apparent depth

real depth = 7.8 cm ; Index of refraction = 1.33

1.33 = 7.8 /apparent depth

apparent depth = 7.8 / 1.33

= 5.86 cm

B )

Distance of fish fro mirror = 20.6 - 7.8 = 12.8 cm

Image will be formed 12.8 cm behind the mirror.

Distance of image from the water surface = 20.6 +12.8

= 33.4 cm

Real depth of image = 33.4

Apparent depth of image = 33.4 / 1.33

= 25.11 cm

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