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BigorU [14]
3 years ago
13

A tank whose bottom is a mirror is filled with water to a depth of 20.6 cm . A small fish floats motionless 7.80 cm under the su

rface of the water. Part A
What is the apparent depth of the fish when viewed at normal incidence to the water?
Express your answer in centimeters. Use 1.33 for the index of refraction of water.
Part B
What is the apparent depth of the reflection of the fish in the bottom of the tank when viewed at normal incidence?
Express your answer in centimeters. Use 1.33 for the index of refraction of water.
Physics
1 answer:
Finger [1]3 years ago
4 0

Answer:

Explanation:

A )  Index of refraction = real depth / apparent depth

real depth = 7.8 cm  ; Index of refraction = 1.33

1.33 = 7.8 /apparent depth

apparent depth = 7.8 / 1.33

= 5.86 cm

B )  

Distance of fish fro mirror = 20.6 - 7.8 = 12.8 cm

Image will be formed 12.8 cm behind the mirror.

Distance of image from the water surface = 20.6 +12.8

= 33.4 cm

Real depth of image = 33.4

Apparent depth of image  = 33.4 / 1.33

= 25.11 cm

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Answer:E=75\ N/m

Explanation:

Given

First charge of q_1=15\ nC is placed at x=1.5\ m

Second charge  q_2=-20\ nC is placed at y=-2\ m

Electric field is given by

E=\frac{kq}{r^2}

Electric field due to q_1 is away from it

E_1=\frac{9\times 10^9\times 15\times 10^{-9}}{(1.5)^2}

E_1=60\ N/m

Electric field due to q_2

E_2=\frac{9\times 10^9\times 20\times 10^{-9}}{2^2}

E_2=45\ N/m

Net electric field will be vector addition of two

\vec{E_{net}}=\vec{E_1}+\vec{E_2}

\vec{E_{net}}=-60\hat{i}-45\hat{j}

Magnitude of Electric field is

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8 0
3 years ago
A driver brings a car to a full stop in 2.0 s. If the car was initially
vagabundo [1.1K]

Answer:

\boxed {\boxed {\sf D. \  -11 \ m/s^2}}

Explanation:

Acceleration can be found by dividing the change in velocity by the time.

a=\frac{v_f-v_i}{t}

where Vf is the final velocity, Vi is the initial velocity, and t is the time.

Since the car came to a complete stop, it's final velocity was 0 meters per second.

The initial velocity was 22 meters per second.

The time was 2.0 seconds.

v_f=0 \ m/s\\v_i=22 \ m/s\\t= 2.0 \ s

Substitute the values into the formula.

a=\frac{0 \ m/s-22 \ m/s}{ 2.0 \s }

Subtract in the numerator first.

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a=\frac{-22 \ m/s}{2.0 \ s}

Divide.

a= -11 \ m/s^2

The acceleration of the car was -11 meters per square second. The negative acceleration indicates slowing down/stopping.

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A man pushes with a force of 200 N on a bookcase of mass 80 kg. The
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Answer: 200 N

Explanation: Apex

7 0
4 years ago
A 75.0 W bulb is connected to a
adoni [48]

Answer:

Explanation:

W = 75 watts

V = 110 volts

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W = V * I

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3 years ago
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Answer:

d) The trampoline pushes back up on the gymnast.

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6 0
3 years ago
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