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nexus9112 [7]
3 years ago
15

The specific heat of a liquid Y is 4.2 cal/g degrees Celsius. A sample grams of this liquid at 137 K is heated to 265K. The liqu

id absorbs. 7.82 kcal. What is the sample of liquid in grams?
Physics
1 answer:
sergiy2304 [10]3 years ago
8 0

Answer:

54

Explanation:

You might be interested in
A material you are testing conducts electricity but cannot be pulled into wires. It is most likely a _____.
notsponge [240]

Answer: The correct answer is "metalloid".

Explanation:

Metal is the material which can conduct electricity as it contains free electrons. It is good conductor of electricity. For example, copper, silver.

Metal can be drawn into wires. This property of material is called ductile.

Metal can be beaten into sheets. This property of material is called malleable.

Non metal is the material which cannot conduct electricity as it does not contain free electrons. They are poor conductor of electricity. For example, oxygen.

Metalloid: It has properties of both metals and non metal. It is electrical conductor. For example, semiconductor- silicon and germanium. But they cannot be pulled into wires.

Therefore, a material you are testing conducts electricity but cannot be pulled into wires. It is most likely a metalloid.

6 0
3 years ago
A student drops a rubber ball onto a surface. Assume that this is a closed system. The ball bounces, but each successive bounce
spayn [35]
I would say D.) The ball bounces many times suggesting the energy is used up efficiently
5 0
2 years ago
Read 2 more answers
A,b, e are complete. Help on the others would be so appreciated!!
bixtya [17]

Answer:

serie Ceq=0.678 10⁻⁶ F  and the charge Q = 9.49 10⁻⁶ C

Explanation:

Let's calculate all capacity values

a) The equivalent capacitance of series capacitors

    1 / Ceq = 1 / C1 + 1 / C2 + 1 / C3 + 1 / C4 + 1 / C5

    1 / Ceq = 1 / 1.5 + 1 / 3.3 + 1 / 5.5 + 1 / 6.2 + 1 / 6.2

    1 / Ceq = 1 / 1.5 + 1 / 3.3 + 1 / 5.5 + 2 / 6.2

    1 / Ceq = 0.666 + 0.3030 +0.1818 +0.3225

    1 / Ceq = 1,147

    Ceq = 0.678 10⁻⁶ F

b) Let's calculate the total system load

   Dv = Q / Ceq

   Q = DV Ceq

   Q = 14 0.678 10⁻⁶

   Q = 9.49 10⁻⁶ C

In a series system the load is constant in all capacitors, therefore, the load in capacitor 5.5 is Q = 9.49 10⁻⁶ C

c) The potential difference

   ΔV = Q / C5

   ΔV = 9.49 10⁻⁶ / 5.5 10⁻⁶

   ΔV = 1,725 ​​V

d) The energy stores is

    U = ½ C V²

    U = ½ 0.678 10-6 14²

    U = 66.4 10⁻⁶ J

e) Parallel system

   Ceq = C1 + C2 + C3 + C4 + C5

   Ceq = (1.5 +3.3 +5.5 +6.2 +6.2) 10⁻⁶

   Ceq = 22.7 10⁻⁶ F

f) In the parallel system the voltage is maintained

   Q5 = C5 V

   Q5 = 5.5 10⁻⁶ 14

   Q5 = 77 10⁻⁶ C

g) The voltage is constant V5 = 14 V

h) Energy stores

   U = ½ C V²

   U = ½ 22.7 10-6 14²

   U = 2.2 10⁻³ J

8 0
3 years ago
At room temperature, sound travels at a speed of about 344 m/s in air. You see a distant flash of lightning and hear the thunder
beks73 [17]

Answer:

d=1.67mi

Explanation:

Assuming the light takes essentially no time to reach you, the distance at which the lightning occurred can be calculated by multiplying the speed of sound by the time it takes to hear the thunder:

d=v_st\\d=344\frac{m}{s}(7.8s)\\d=2683.2m*\frac{1mi}{1609.34m}=1.67mi

4 0
3 years ago
A 50.0-kg bungee jumper steps off a bridge with a light bungee cord tied to her and to the bridge. The unstretched length of the
lina2011 [118]

Answer:

The the analysis for the free fall part should be done under the constant acceleration.

Explanation:

In the given problem, the jumper is falling under the free fall. Since, no external force is acting on the body therefore, the fall will be under the action gravity only. also, the acceleration due to gravity is always constant.

Therefore, the the analysis for the free fall part should be done under the constant acceleration.

8 0
2 years ago
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